【poj1568】 Find the Winning Move】的更多相关文章

http://poj.org/problem?id=1568 (题目链接) 题意 两人下4*4的井字棋,给出一个残局,问是否有先手必胜策略. Solution 极大极小搜索.. 这里有个强力优化,若已经被下了的的格子数cnt小于等于4的话,那么一定是平局至于为什么,自己YY一下发现好像是这样的.. 代码 // poj1568 #include<algorithm> #include<iostream> #include<cstring> #include<cstd…
Description 4x4 tic-tac-toe is played on a board with four rows (numbered 0 to 3 from top to bottom) and four columns (numbered 0 to 3 from left to right). There are two players, x and o, who move alternately with x always going first. The game is wo…
poj  1568:Find the Winning Move   [迭代博弈+搜索+剪枝] 题面省略... Input The input contains one or more test cases, followed by a line beginning with a dollar sign that signals the end of the file. Each test case begins with a line containing a question mark and…
[CF653G]Move by Prime 题意:给你一个长度为n的数列$a_i$,你可以进行任意次操作:将其中一个数乘上或者除以一个质数.使得最终所有数相同,并使得操作数尽可能小.现在我们想要知道$a_i$的所有子序列的操作数之和是多少.答案对$10^9+7$取模. $n,a_i\le 3\times 10^5$ 题解:显然要对每个质数分别处理.而对于每个质数,最终一定是让所有数都变成该序列的中位数最优.因此如果所有数的次数分别是$k_1,k_2...k_n$,则如果i在中位数左边,则贡献为$…
283. Move Zeroes[easy] Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3…
Find the Winning Move Time Limit: 3000MS   Memory Limit: 32768K Total Submissions: 1286   Accepted: 626 Description 4x4 tic-tac-toe is played on a board with four rows (numbered 0 to 3 from top to bottom) and four columns (numbered 0 to 3 from left t…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 考虑删掉第i位. 则第i+1位就会取代第i位. 则肯定第i+1位比第i位大的话,才比较好. 则从小到大贪心删,找到第一个a[i+1]>a[i]的i. 然后每次删掉这样的i就可以了. [代码] /* 1.Shoud it use long long ? 2.Have you ever test several sample(at least therr) yourself? 3.Can you promise that the s…
[题目] Description Adam and Eve enter this year's ACM International Collegiate Programming Contest. Last night, they played the Calendar Game, in celebration of this contest. This game consists of the dates from January 1, 1900 to November 4, 2001, the…
基本数据类型补充: set 是一个无序且不重复的元素集合 class set(object): """ set() -> new empty set object set(iterable) -> new set object Build an unordered collection of unique elements. """ def add(self, *args, **kwargs): # real signature un…
  ×   缘起---闲逛博客园 前几天的时候,在某一QQ群看到一条消息“XXX酒店开房XXXBTXX迅雷BT下载”,当时是一目十行的心态浏览,目光掠过时, 第一反应我想多了~以为是XX种子(你懂的~),但并不感兴趣. 直到又回到博客园逛时,看到一篇最多评论的文章: 看看多线程的效率有多差劲! - 张浩华 - 博客园 http://www.cnblogs.com/zhhh/p/3385751.html 于是点击进去了.这时,我才回想起来,当时是自己邪想多了...... 原来是2000w条开房数据…