HDU 1162Eddy's picture(MST问题)】的更多相关文章

Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11841    Accepted Submission(s): 5922 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to…
[题目] Picture Problem Description A number of rectangular posters, photographs and other pictures of the same shape are pasted on a wall. Their sides are all vertical or horizontal. Each rectangle can be partially or totally covered by the others. The…
Eddy's picture Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 29   Accepted Submission(s) : 26 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Eddy begins to like pa…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5627 题意:Bestcoder的一道题,让你求&意义下的最大生成树. 解法: 贪心,我们从高位到低位贪心,如果含有这一位的边能够构成一棵树的话,我们就可以直接把其他不含有这一位的边全部去掉 然后重复这个行为 这个贪心显然正确啦,至于判断能否构成一颗树,就用并查集就好啦 //HDU 5627 #include <bits/stdc++.h> using namespace std; cons…
The Unique MST Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24152   Accepted: 8587 Description Given a connected undirected graph, tell if its minimum spanning tree is unique. Definition 1 (Spanning Tree): Consider a connected, undire…
Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4487 Accepted Submission(s): 2209 Problem Description A number of rectangular posters, photographs and other pictures of the same shape are pasted o…
畅通工程 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14103    Accepted Submission(s): 5824 Problem Description 省政府"畅通工程"的目标是使全省任何两个村庄间都可以实现公路交通(但不一定有直接的公路相连,只要能间接通过公路可达即可).经过调查评估,得到的统计表中列出了…
Problem Description Clarke is a patient with multiple personality disorder. One day he turned into a learner of graph theory.  He learned some algorithms of minimum spanning tree. Then he had a good idea, he wanted to find the maximum spanning tree w…
题意:给一张由白边和黑边构成的无向图,求是否存在一个生成树,使白边的数量为一个斐波那契数. 分析:白边权值为1,黑边权值为0.求出该图的最小生成树和最大生成树,若这两个值之间存在斐波那契数,则可以,若不存在或者所给的图不是连通图,则不行. #include<bits/stdc++.h> using namespace std; const int maxn = 1e5+5; typedef long long LL; set<int> dp; struct Edge{ int u,…
题目链接 题意 给出n个矩形,求周长并. 思路 学了区间并,比较容易想到周长并. 我是对x方向和y方向分别做两次扫描线.应该记录一个pre变量,记录上一次扫描的时候的长度,对于每次遇到扫描线统计答案的时候,使用当前的 tree[1] 去与 pre 做相减,因为这一次如果边长增加了或者减少了,那么一定和之前的值有差值,其中的差值就是这次的变化量. 但是这份代码交G++会WA,C++就A了.而且排序的时候如果权值相同,应该让状态为1(开始)的扫描线排在状态为-1(结束)的扫描线前面,因为重合的话,那…