有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+A[j])/(A[i]*A[j])) return sum 给出数组A,由你来计算fun(A)的结果.例如:A = {1, 4, 1},fun(A) = [5/4] + [2/1]…
有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+A[j])/(A[i]*A[j])) return sum 给出数组A,由你来计算fun(A)的结果.例如:A = {1, 4, 1},fun(A) = [5/4] + [2/1]…
HackerRank 1305 Pairwise Sum and Divide 有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+A[j])/(A[i]*A[j])) return sum 给出数组A,由你来计算fun(A…
1305 Pairwise Sum and Divide 题目来源: HackerRank 基准时间限制:1 秒 空间限制:131072 KB 分值: 5 难度:1级算法题 有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+A[j])/(A[i…
久しぶり! 发现的一道有意思的题,想了半天都没有找到规律,结果竟然是思路题..(在大佬题解的帮助下) 原题戳>>https://www.51nod.com/onlineJudge/questionCode.html#!problemId=1305<< 有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length …
1305 Pairwise Sum and Divide 题目来源: HackerRank 基准时间限制:1 秒 空间限制:131072 KB 分值: 5 难度:1级算法题 收藏 关注 有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+A[j]…
1305 Pairwise Sum and Divide 题目来源: HackerRank 基准时间限制:1 秒 空间限制:131072 KB 分值: 5 难度:1级算法题 收藏 关注 有这样一段程序,fun会对整数数组A进行求值,其中Floor表示向下取整: fun(A) sum = 0 for i = 1 to A.length for j = i+1 to A.length sum = sum + Floor((A[i]+…