1.Two sum (Easy)# Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given num…
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 思路:由于只能向两个方向走,瞬间就没有了路线迂回的烦恼,题目的难度…
Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…
原题地址:https://oj.leetcode.com/problems/path-sum-ii/ 题意: Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example:Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5…
1.类中递归调用函数需要加self # Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param root, a tree node # @param sum, an integer # @return a boolean def hasPath…
题目: Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 代码:oj测试通过 Runtime: 102 ms cla…
原题链接 题意: 给定一个值,求出从树顶到某个叶(没有子节点)有没有一条路径等于该值. 思路: DFS Runtime: 4 ms, faster than 100.00% of C++ class Solution { public: bool hasPathSum(TreeNode *root, int sum) { if (root == NULL) return false; if (root->val == sum && root->left==NULL &&…
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi…
Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the sameelement twice. Example: Given nums = [2, 7, 11, 15],…
Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15]…
题目: Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note t…
leetcode python solution 1. two sum (easy) Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15],…
Python之 continue继续循环 在循环过程中,可以用break退出当前循环,还可以用continue跳过后续循环代码,继续下一次循环. 假设我们已经写好了利用for循环计算平均分的代码: L = [75, 98, 59, 81, 66, 43, 69, 85] sum = 0.0 n = 0 for x in L: sum = sum + x n = n + 1 print sum / n 现在老师只想统计及格分数的平均分,就要把 x < 60 的分数剔除掉,这时,利用 continu…
条件判断经常使用if语句进行判断,表达方式为:if 条件语句: :elif:else if...用于执行第一条不满足if的判断,继续执行其它的判断.比如一个简单的if判断 Python3取消了raw_input(),使用input()接受输入,如果需要,在input()前加上限定条件int or float,默认str不用添加. score = int(input('input your score')) if num >= 80: print("excellllent!&quo…
