CodeForcesGym 100676H Capital City】的更多相关文章

H. Capital City Time Limit: 3000ms Memory Limit: 262144KB This problem will be judged on CodeForcesGym. Original ID: 100676H64-bit integer IO format: %I64d      Java class name: (Any)   Bahosain has become the president of Byteland, he is doing his b…
H. Capital City[ Color: Black ]Bahosain has become the president of Byteland, he is doing his best to make people's liveseasier. Now, he is working on improving road networks between the cities.If two cities are strongly connected, people can use BFS…
https://vjudge.net/problem/Gym-100676H 题意: 给出一个n个城市,城市之间有距离为w的边,现在要选一个中心城市,使得该城市到其余城市的最大距离最短.如果有一些城市是强连通的,那么他们可以使用传送门瞬间到达. 思路:因为强连通时可以瞬移,因为是无向图,所以计算边双连通分量然后重新建图,这样,也就不存在环了. 接下来,计算一下树的直径,因为中心城市肯定选在树的直径上,这样才有可能使最大的边最短. #include<iostream> #include<a…
题目链接:http://codeforces.com/gym/100676/attachments 题意: 有 n 个点,m 条边,图中,边强连通分量之间可以直达,即距离为 0 ,找一个点当做首都,其他点到首都的最大距离最小. 参考:http://www.cnblogs.com/ost-xg/p/6395100.html 仔细研究了大佬的思路,很牛逼,但是也有一点细节遗漏了,但是还是能AC,interesting: 分析: 边双连通:条件比点双连通松一点,体现在程序中,就是存在一个子节点能到达的…
感觉题目都已经快把正解给说出来了...strongly connected的两个点的消耗为0,其实就是同一个边双连通分量里面的点消耗为0.然后缩一下点,再树形DP一下就完了.第一次写边双,但感觉挺简单的. #include <bits/stdc++.h> #define ll long long using namespace std; ; int c[N]; ]; struct E { int v, ne; ll c; } e[N * ], tree[N * ]; int head[N],…
A(By talker): 题意分析:以a(int) op b(int)形式给出两个整数和操作符, 求两个整数是否存在操作符所给定的关系 ,有则输出true,无则输出false: 思路:由于无时间复杂度的限制,做为 签到题怎么快怎么写(比赛时,赛后 可以考虑尽量压缩代码),裸暴 力,if else拉伸判断每一个就 好了..处理起来的难点可能是中间字 符的读入处理,可以用%s读入然 后strcmp判断,反正怎么无 脑怎么写好了 B (By 2981405123): http://www.jians…
Problem Statement      There is a country with n cities, numbered 0 through n-1. City 0 is the capital. The road network in the country forms an undirected connected graph. In other words: Some pairs of cities are connected by bidirectional roads. Fo…
Swift使用自动引用计数(ARC)机制来跟踪和管理你的应用程序的内存.通常情况下,Swift 内存管理机制会一直起作用,你无须自己来考虑内存的管理.ARC 会在类的实例不再被使用时,自动释放其占用的内存.然而,在少数情况下,ARC 为了能帮助你管理内存,需要更多的关于你的代码之间关系的信息. 参考练习代码: import Foundation // Swift使用自动引用计数(ARC)机制来跟踪和管理你的应用程序的内存. // 引用计数仅仅应用于类的实例.结构体和枚举类型是值类型,不是引用类型…
Qin Shi Huang's National Road System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6137    Accepted Submission(s): 2143 Problem Description During the Warring States Period of ancient China(47…
The world of Blade and Soul, is a vast extension of land containing two continents (the Southern Continent and the Eastern Continent) with four major zones: Viridian Coast, The Cinderlands, Moonwater Plains and Silverfrost Mountains. Each Zone is fur…