【Leetcode 83 Remove Duplicates from Sorted List 链表】的更多相关文章

Leetcode 83 Remove Duplicates from Sorted List 链表

就是将链表中的重复元素去除 我的方法很简单就是如果链表的前后元素相同的话,将后一个元素删除 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* he…

[LeetCode] 83. Remove Duplicates from Sorted List 移除有序链表中的重复项

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 这道题让我们移除给定有序链表的重复项,那么可以遍历这个链表,每个结点和其后面的结点比较,如果结点值相…

[LeetCode] 83. Remove Duplicates from Sorted List ☆(从有序链表中删除重复项)

描述 Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2Output: 1->2Example 2: Input: 1->1->2->3->3Output: 1->2->3 有序链表去重. 解析 移除给定有序链表的重复项,那么我们可以遍历这个链表,每个结点和其后面的结点比较…

[leetcode]83. Remove Duplicates from Sorted List有序链表去重

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 题意: 有序链表去重 思路: 代码: class Solution { public ListNod…

LeetCode 83. Remove Duplicates from Sorted List （从有序链表中去除重复项）

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 题目标签:Linked List 题目给了我们一个 list,让我们去除中间的重复项. 设一个 cursor = head…

[LeetCode]83. Remove Duplicates from Sorted List(排序链表去重)

Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 设置2个指针,cur 和next. 当cur的值与next的值相等时,cur.next= next.next   更新ne…

leetCode 83.Remove Duplicates from Sorted List（删除排序链表的反复） 解题思路和方法

Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 思路:此题与上一题异曲同工,详细解法例如以下: /** * Definition for singly-linked…

LeetCode 83. Remove Duplicates from Sorted List（从有序链表中删除重复节点）

题意:从有序链表中删除重复节点. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* head) { if(head == NULL || head…

Java [Leetcode 83]Remove Duplicates from Sorted List

题目描述: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 代码如下: 代码一,正常解法: /** * Definition for singly-linked list…

[LeetCode] 83. Remove Duplicates from Sorted List_Easy tag: Linked List

Given a sorted linked list, delete all duplicates such that each element appear only once. Example 1: Input: 1->1->2 Output: 1->2 Example 2: Input: 1->1->2->3->3 Output: 1->2->3 利用dummy head,将head 和head.next 比较(如果head.next存在的话),…