LeetCode_350. Intersection of Two Arrays II】的更多相关文章

350. Intersection of Two Arrays II Easy Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each…
problem 350. Intersection of Two Arrays II 不是特别明白这道题的意思,例子不够说明问题: 是按顺序把相同的元素保存下来,还是排序,但是第二个例子没有重复.... 参考 1. Leetcode_350. Intersection of Two Arrays II; 2. CSDN_blogs; 完…
Given two arrays, write a function to compute their intersection.Notice Each element in the result should appear as many times as it shows in both arrays.    The result can be in any order. Example Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return […
350. Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both…
这两道题都是求两个数组之间的重复元素,因此把它们放在一起. 原题地址: 349 Intersection of Two Arrays :https://leetcode.com/problems/intersection-of-two-arrays/description/ 350 Intersection of Two Arrays II:https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 题目&&am…
169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…
原题链接在这里:https://leetcode.com/problems/intersection-of-two-arrays-ii/ 题目: Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appe…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in t…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…
""" Intersection of Two Arrays Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] ""…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…
/* Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…
题目描述: Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in a…
题目如下: Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in…
题目描述: 给定两个数组求他们的公共部分,输出形式是数组,相同的元素累计计数 例如: nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. 原文描述: Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element i…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…
Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…
题目: 给定两个数组,编写一个函数来计算它们的交集. Given two arrays, write a function to compute their intersection. 示例 1: 输入: nums1 = [1,2,2,1], nums2 = [2,2] 输出: [2,2] 示例 2: 输入: nums1 = [4,9,5], nums2 = [9,4,9,8,4] 输出: [4,9] 说明: 输出结果中每个元素出现的次数,应与元素在两个数组中出现的次数一致. 我们可以不考虑输出…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…
Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] class Solution { public int[] intersect(int[] nums…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4044 访问. 给定两个数组,编写一个函数来计算它们的交集. 输入: nums1 = [1,2,2,1], nums2 = [2,2] 输出: [2,2] 输入: nums1 = [4,9,5], nums2 = [9,4,9,8,4] 输出: [4,9] 说明: 输出结果中每个元素出现的次数,应与元素在两个数组中出现的次数一致. 我们可以不考虑输出结果的顺序.…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 Java排序+双指针 Python排序+双指针 Python解法使用字典 日期 Difficulty: Easy 题目描述 Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Ou…
这是悦乐书的第208次更新,第220篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第76题(顺位题号是350).给定两个数组,编写一个函数来计算它们的交集.例如: 输入:nums1 = [1,2,2,1],nums2 = [2,2] 输出:[2,2] 输入:nums1 = [4,9,5],nums2 = [9,4,9,8,4] 输出:[4,9] 注意: 结果中的每个元素应该出现在两个数组中显示的次数. 结果可以是任何顺序. 跟进: 如果给定的数组已经排序怎么办? 你…
List<Integer> res = new ArrayList<>(); Arrays.sort(nums1); Arrays.sort(nums2); int i1 = 0; int i2 = 0; while (i1<nums1.length&&i2<nums2.length) { if (nums1[i1]<nums2[i2]) i1++; else if (nums1[i1]>nums2[i2]) i2++; else { res…
#-*- coding: UTF-8 -*- class Solution(object):    def intersect(self, nums1, nums2):                if len(nums1)<len(nums2):            tmp=nums1            nums1=nums2            nums2=tmp               tmpdic={}               for num in nums1:    …
给定两个数组,写一个方法来计算它们的交集.例如:给定 nums1 = [1, 2, 2, 1], nums2 = [2, 2], 返回 [2, 2].注意:       输出结果中每个元素出现的次数,应与元素在两个数组中出现的次数一致.       我们可以不考虑输出结果的顺序.跟进:    如果给定的数组已经排好序呢?你将如何优化你的算法?    如果 nums1 的大小比 nums2 小很多,哪种方法更优?    如果nums2的元素存储在磁盘上,内存是有限的,你不能一次加载所有的元素到内存…