题目地址:http://poj.org/problem?id=2785 #include<cstdio> #include<iostream> #include<string.h> #include<algorithm> #include<math.h> #include<stdbool.h> #include<time.h> #include<stdlib.h> #include<set> #in…

传送门 4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 20334   Accepted: 6100 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 13069   Accepted: 3669 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 25615   Accepted: 7697 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 25675   Accepted: 7722 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS Memory Limit: 228000K Total Submissions: 26974 Accepted: 8133 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how man…

题目链接: https://cn.vjudge.net/problem/POJ-2785 The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we…

[题目链接] http://poj.org/problem?id=2785 [题目大意] 给出四个数组,从每个数组中选出一个数,使得四个数相加为0,求方案数 [题解] 将a+b存入哈希表,反查-c-d [代码] #include <cstdio> #include <algorithm> #include <cstring> using namespace std; const int N=4500,mod=1<<22; int n,a[N],b[N],c[…

http://poj.org/problem?id=2785 题目大意: 给你四个数组a,b,c,d求满足a+b+c+d=0的个数 其中a,b,c,d可能高达2^28 思路: 嗯,没错,和上次的 HDU 1496 Equations hash(见http://blog.csdn.net/murmured/article/details/17596655)差不多,但是那题数据量小,hash值很好得到,不用取模运算. 而这题数据量很大.那就采用开散列的思想. hash值怎么选取? 上次我看的书中是建…

Description The SUM problem can be formulated . In the following, we assume that all lists have the same size n . Input The first line of the input file contains the size of the lists n (). We then have n lines containing four integer values (with ab…

思路: 如果用朴素的方法算O(n^4)超时,这里用折半二分.把数组分成两块,分别计算前后两个的和,然后枚举第一个再二分查找第二个中是否有满足和为0的数. 注意和有重复 #include<iostream> #include<algorithm> #include<cstring> #define ll long long using namespace std; const int N = 4000+5; int a[N],b[N],c[N],d[N]; int mp1…

给出四个长度为n的数列a,b,c,d,求从这四个数列中每个选取一个元素后的和为0的方法数.n<=4000,abs(val)<=2^28. 考虑直接暴力,复杂度O(n^4).显然超时. # include <cstdio> # include <cstring> # include <cstdlib> # include <iostream> # include <vector> # include <queue> # in…

2017-08-01 21:29:14 writer:pprp 参考:http://blog.csdn.net/piaocoder/article/details/45584763 算法分析:直接暴力复杂度过高,所以要用二分的方法,分成两半复杂度就会大大降低: 题目意思:给定4个n(1<=n<=4000)元素的集合 A.B.C.D ,从4个集合中分别选取一个元素a, b,c,d.求满足 a+b+c+d=0的个数 代码如下: //首先将前两列任意两项相加得到数组x,再将后两列任意两项相加取反得到…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 29243   Accepted: 8887 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 18221   Accepted: 5363 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS Memory Limit: 228000K Total Submissions: 17875 Accepted: 5255 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how man…

4 Values whose Sum is 0 Time Limit: 15000MS Memory Limit: 228000K Total Submissions: 19322 Accepted: 5778 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how man…

K - 4 Values whose Sum is 0 Crawling in process... Crawling failed Time Limit:9000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 1152 Appoint description: System Crawler (2015-03-12) Description   The SUM problem c…

4 Values whose Sum is 0 题目链接:https://cn.vjudge.net/problem/UVA-1152 ——每天在线,欢迎留言谈论. 题目大意: 给定4个n(1<=n<=4000)元素的集合 A.B.C.D ,从4个集合中分别选取一个元素a, b,c,d.求满足 a+b+c+d=0的对数. 思路: 直接分别枚举 a,b,c,d ,坑定炸了.我们先枚举 a+b并储存,在B.C中枚举找出(-c-d)后进行比较即可. 亮点: 由于a+b,中会有值相等的不同组合,如果使…

Problem UVA1152-4 Values whose Sum is 0 Accept: 794  Submit: 10087Time Limit: 9000 mSec Problem Description The SUM problem can be formulated as follows: given four lists A,B,C,D of integer values, compute how many quadruplet (a,b,c,d) ∈ A×B×C×D are…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 21370   Accepted: 6428 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

4 Values whose Sum is 0 Time Limit: 15000MS   Memory Limit: 228000K Total Submissions: 23757   Accepted: 7192 Case Time Limit: 5000MS Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how…

G - 4 Values whose Sum is 0 The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we assume that all…

题目链接:http://poj.org/problem?id=2785 题意是给你4个数列.要从每个数列中各取一个数,使得四个数的sum为0,求出这样的组合的情况个数. 其中一个数列有多个相同的数字时,把他们看作不同的数字. 做法是把前两个数列和的值存在一个数组(A)中 , 后两个数列的和存在另一个数组(B)中 , 数组都为n^2 . 然后将B数组sort一下 , 将A数组遍历 , 二分查找一下B数组中与A数组元素和为0的个数 . 有个注意的点是万一A数组都是0 , 而B数组都为0的情况(还有其…

题目链接 Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following, we assume that all lists have…

找四个数的和为0 题目大意:给定四个集合,要你每个集合选4个数字,组成和为0 这题是3977的简单版,只要和是0就可以了 #include <iostream> #include <algorithm> #include <functional> #define MAX 4001 using namespace std; typedef long long LL_INT; ][MAX], set_sum1[MAX*MAX]; LL_INT *Binary_Lower_B…

题意:输入一个数字n,代表有n行a,b,c,d,求a+b+c+d=0有多少组情况. 思路:先求出前两个数字的所有情况,装在一个数组里面,再去求后两个数字的时候二分查找第一个大于等于这个数的位置和第一个大于这个数的位置相减,得出有多少个答案,累加得出最终答案. 过程: 刚开始写的时候,用的是map把原来的答案存起来,后来发现超时,因为在存数的时候和取数的时候都消耗时间,所以就用容器直接存,二分查找得出答案,结果二分函数又忘了,于是自己尝试着写了一个,就过了. lower_bound(v.begin…

题意: A,B,C,D四组数中各取一个数,使这四个数相加为0,问有多少组取法? 分析: 四个数列有n4种取法,规模较大,但是可以将他们分成AB,CD两组,分别枚举,最后再合并. 代码: #include<cstdio> #include<algorithm> #include<iostream> using namespace std; typedef long long ll; const int maxn = 4005, maxm = 16000025; int c…

传送门:http://poj.org/problem?id=2785 Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B x C x D are such that a + b + c + d = 0 . In the following,…

  Time Limit:15000MS     Memory Limit:228000KB     64bit IO Format:%I64d & %I64u Submit Status Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer values, compute how many quadruplet (a, b, c, d ) ∈ A x B…