https://leetcode-cn.com/problems/range-sum-of-bst/ 二叉树中序遍历 二叉搜索树性质:一个节点大于所有其左子树的节点,小于其所有右子树的节点 /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ clas…

给定二叉搜索树的根结点 root,返回 L 和 R(含)之间的所有结点的值的和. 二叉搜索树保证具有唯一的值. 示例 1: 输入:root = [10,5,15,3,7,null,18], L = 7, R = 15 输出:32 示例 2: 输入:root = [10,5,15,3,7,13,18,1,null,6], L = 6, R = 10 输出:23 提示: 树中的结点数量最多为 10000 个. 最终的答案保证小于 2^31. 二叉树有关的一般都是递归求解 class Solution…

Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes. Example: Input: 1 \ 3 / 2 Output: 1 Explanation: The minimum absolute difference is 1, which is the difference between 2 and 1…

import functools # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None @functools.lru_cache() class Solution(object): def rangeSumBST(self, root, L, R): ""&q…

problem 938. Range Sum of BST 参考 1. Leetcode_easy_938. Range Sum of BST; 完…

LeetCode:将有序数组转换为二叉搜索树[108] 题目描述 将一个按照升序排列的有序数组,转换为一棵高度平衡二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1. 示例: 给定有序数组: [-10,-3,0,5,9], 一个可能的答案是:[0,-3,9,-10,null,5],它可以表示下面这个高度平衡二叉搜索树: 0 / \ -3 9 / / -10 5 题目分析 BST树的建立是唯一的吗?即使给定有序数组,我认为BST也是是不唯一的.…

数据结构中常见的树(BST二叉搜索树.AVL平衡二叉树.RBT红黑树.B-树.B+树.B*树) 二叉排序树.平衡树.红黑树 红黑树----第四篇:一步一图一代码,一定要让你真正彻底明白红黑树 --- 很好…

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput…

Given a binary search tree and a node in it, find the in-order successor of that node in the BST. The successor of a node p is the node with the smallest key greater than p.val. Example 1: Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-or…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}"…