Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? Credits:Special thanks to @yukuairoyfor…

传送门 Description Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 思路 题意:不使用循环和递归,求一个数是否是4的…

题目描述: Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. 解题思路: 位操作. 首先判断是不是只有一位数字为1,其余为0 然后判断为1的位置是不是奇数位 代码如下: class Solution(object): def isPower…

Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 题目标签:Bit Manipulation 这道题目让我们判断一个数字是不是4的…

Given an integer (signed 32 bits), write a function to check whether it is a power of 4. Example:Given num = 16, return true. Given num = 5, return false. Follow up: Could you solve it without loops/recursion? 先说明用循环: 如下 class Solution { public: bool…

题意:判断一个数是不是4的幂数,和Power of two类似. 先判断num是否大于0,再判断num是否能开根号,最后判断num开根号后的数是否是2^15的约数. 提示:4的幂数开根号就是2的幂数. 注意:判断一个双精度数a是否是0,请用fabs(a)<一个极小的数,如本题中用的是1e-9. class Solution { public: bool isPowerOfFour(int num) { ) && (fabs(( ) && ((<<) % (…

这三道题目都是一个意思,就是判断一个数是否为2/3/4的幂,这几道题里面有通用的方法,也有各自的方法,我会分别讨论讨论. 原题地址:231 Power of Two:https://leetcode.com/problems/power-of-two/description/ 326 Power of Three:https://leetcode.com/problems/power-of-three/description/ 342 Power of Four :https://leetcod…

Given an integer, write a function to determine if it is a power of two. Example 1: Input: 1 Output: true Example 2: Input: 16 Output: true Example 3: Input: 218 Output: false 给一个整数,写一个函数来判断它是否为2的次方数. 利用计算机用的是二进制的特点,用位操作,此题变得很简单. 2的n次方的特点是:二进制表示中最高位是…

231. Power of Two Given an integer, write a function to determine if it is a power of two. class Solution { public: bool isPowerOfTwo(int n) { ? (n & (n-)) == : false; } }; 342. Power of Four Given an integer (signed 32 bits), write a function to che…

leetcode 326. Power of Three(不用循环或递归) Given an integer, write a function to determine if it is a power of three. Follow up: Could you do it without using any loop / recursion? 题意是判断一个数是否是3的幂,最简单的也最容易想到的办法就是递归判断,或者循环除. 有另一种方法就是,求log以3为底n的对数.类似 如果n=9,则…