Codeforces1312E Array Shrinking 区间DP】的更多相关文章

题意 给你一个数组\(a\),只要满足\(a_i=a_{i+1}\)就可以将这两个元素合并成一个值为\(a_i+1\)的元素,问数组最小长度. 解题思路 记得之前某场的F和这题差不多,当时好像是相邻且相等就可以移除这两个数问最小长度. 看到\(n\)的范围就想到区间DP了,感觉是一道挺裸的区间DP板子题. AC代码 #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int,in…
题目链接: Bomber Man wants to bomb an Array. Time Limit: 4000/2000 MS (Java/Others)     Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 382    Accepted Submission(s): 114 Problem Description Given an array and some positions where to plant…
E. Array Shrinking 题目大意: 给你一个大小是n的序列,相邻的序列如果相等,则可以合并,合并之后的值等于原来的值加1. 求:合并之后最小的序列的和. 题解: 这个数据范围和这个相邻的合并一看就知道是一个区间 \(dp\) 说难也难,说不难也不难,如果知道区间 \(dp\) 的基本解法,那就会写了. \(dp[i][j]\) 表示的是从 \(i\) 到 \(j\) 这个区间合并之后的最小的值. 再用一个 \(val[i][j]\) 表示 \(i\) 到 \(j\) 这个区间合并后…
题目链接 http://lightoj.com/volume_showproblem.php?problem=1031 Description You are playing a two player game. Initially there are n integer numbers in an array and player A and B get chance to take them alternatively. Each player can take one or more nu…
题目连接:http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=19461 Game of sum Description This is a two player game. Initially there are n integer numbers in an array and players A and B getchance to take them alternatively. Each player can take…
Problem Description IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding Inform…
E - Multi-bit Trie Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest P…
题目描述 Vasya has a string s of length n consisting only of digits 0 and 1. Also he has an array a of length n. Vasya performs the following operation until the string becomes empty: choose some consecutive substring of equal characters, erase it from t…
题目链接 Problem Description IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding I…
4380: [POI2015]Myjnie Time Limit: 40 Sec  Memory Limit: 256 MBSec  Special JudgeSubmit: 162  Solved: 82[Submit][Status][Discuss] Description 有n家洗车店从左往右排成一排,每家店都有一个正整数价格p[i].有m个人要来消费,第i个人会驶过第a[i]个开始一直到第b[i]个洗车店,且会选择这些店中最便宜的一个进行一次消费.但是如果这个最便宜的价格大于c[i],…