Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1. Examp…

版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 414. Third Maximum Number题解 在线提交: https://leetcode-cn.com/problems/third-maximum-number 题目描述 414. 第三大的数 给定一个非空数组,返回此数组中第三大的数.如果不存在,则返回数组中最大的数.…

problem 414. Third Maximum Number solution 思路:用三个变量first, second, third来分别保存第一大.第二大和第三大的数,然后遍历数组. class Solution { public: int thirdMax(vector<int>& nums) { //1.LONG_MIN; long first = LONG_MIN, second = LONG_MIN, third = LONG_MIN;// for(auto a:n…

Description Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [, , ] Output: Explanation: The third maximum .  E…

Problem: Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [3, 2, 1] Output: 1 Explanation: The third maximum is…

Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1. Examp…

［抄题］: Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n). Example 1: Input: [3, 2, 1] Output: 1 Explanation: The third maximum is 1.…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 替换最大值数组 使用set 三个变量 日期 题目地址:https://leetcode.com/problems/third-maximum-number/description/ 题目描述 Given a non-empty array of integers, return the third maximum number in this arr…

#-*- coding: UTF-8 -*- #l1 = ['1','3','2','3','2','1','1']#l2 = sorted(sorted(set(l1),key=l1.index,reverse=False),reverse=True)class Solution(object):    def thirdMax(self, nums):        """        :type nums: List[int]        :rtype: int  …

这个题有点坑啊..主要是自己蠢,以为 Integer.MIN_VALUE -1 == -2147483649 public class Solution { public int thirdMax(int[] nums) { long max = (long)Integer.MIN_VALUE-1, mid = (long)Integer.MIN_VALUE-1, min = (long)Integer.MIN_VALUE-1; for(int j: nums) { long i = (long…