[LC] 71. Simplify Path】的更多相关文章

Given an absolute path for a file (Unix-style), simplify it. Or in other words, convert it to the canonical path. In a UNIX-style file system, a period . refers to the current directory. Furthermore, a double period .. moves the directory up a level.…
71. Simplify Path Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", => "/c" click to show corner cases. Corner Cases: Did you consi…
[LeetCode]71. Simplify Path 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/simplify-path/description/ 题目描述: Given an absolute path for a file (Unix-style), simplify it. For e…
Simplify Path Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" click to show corner cases. Corner Cases: Did you consider th…
[抄题]: Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩corner case]: 空格属…
Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" click to show corner cases. Corner Cases: Did you consider the case where p…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", =…
Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", => "/c" 注意:题目中已限定是absolute path - contains the root directory and all other subdi…
Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" Corner Cases: Did you consider the case where path = "/../"?In th…
原题地址 用栈保存化简后的路径.把原始路径根据"/"切分成若干小段,然后依次遍历 若当前小段是"..",弹栈 若当前小段是".",什么也不做 否则,入栈 代码: string simplifyPath(string path) { vector<string> buffer; char *tok = NULL; tok = strtok((char *) path.c_str(), "/"); while (tok…