题目链接:http://codeforces.com/problemset/problem/689/B 题目大意: 留坑 明天中秋~…
Mike and Shortcuts 题目链接: http://acm.hust.edu.cn/vjudge/contest/121333#problem/F Description Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city. City consists of n i…
B. Mike and Shortcuts time limit per test: 3 seconds memory limit per test: 256 megabytes input: standard input output: standard output Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some si…
题目大意:给出n个点,两点间的常规路为双向路,路长为两点之间的差的绝对值,第二行为捷径,捷径为单向路(第i个点到ai点),距离为1.问1到各个点之间的最短距离. 题目思路:SPFA求最短路 #include<iostream> #include<algorithm> #include<cstring> #include<vector> #include<stdio.h> #include<stdlib.h> #include<q…
codeforces 689 Mike and Shortcuts(最短路) 原题 任意两点的距离是序号差,那么相邻点之间建边即可,同时加上题目提供的边 跑一遍dijkstra可得1点到每个点的最短路,时间复杂度是O(mlogm) #include <cstdio> #include <iostream> #include <cstring> #include <queue> #include <vector> using namespace s…
题目链接: B. Mike and Shortcuts time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some…
B. Mike and Shortcuts 题目连接: http://www.codeforces.com/contest/689/problem/B Description Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city. City consists of n inter…
B. Mike and Shortcuts time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight…
hdu4135 求[L,R]范围内与N互质的数的个数. 分别求[1,L]和[1,R]和n互质的个数,求差. 利用容斥原理求解. 二进制枚举每一种质数的组合,奇加偶减. #include <bits/stdc++.h> using namespace std; typedef long long ll; ; int fac[N], cnt; void factor(int n) { cnt = ; int limit = sqrt(n); ; i <= limit; ++i) { ) fa…
codeforces 547E Mike and Friends 题意 题解 代码 #include<bits/stdc++.h> using namespace std; #define fi first #define se second #define mp make_pair #define pb push_back #define rep(i, a, b) for(int i=(a); i<(b); i++) #define per(i, a, b) for(int i=(b)…