首先,只需要找到一个有磁性的位置,就可以通过$n-1$次判断其余磁铁是否有磁性,因此也就是要在$\lfloor\log_{2}n\rfloor+1$次中找到一个有磁性的位置 有一个$n-1$次的做法,即暴力枚举第$i$个磁铁($i\ge 2$),将1到$i-1$的磁铁放在左侧,那么一定能找到第2个有磁性的磁铁,由于总存在两个,即可以找到 事实上,找磁铁已经无法优化了,但找磁铁的过程却可以带来额外的信息:假设第一个磁铁位于$i$,$i$之前恰好存在一个磁铁,对$i$之前的部分二分即可 更精确的来说…

C. Edo and Magnets Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/594/problem/C Description Edo has got a collection of n refrigerator magnets! He decided to buy a refrigerator and hang the magnets on the door. The shop ca…

Problem description Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If…

CodeForces - 344A id=46664" style="color:blue; text-decoration:none">Magnets Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Submit Status Description Mad scientist Mike entertains himself by arranging ro…

Description Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two mag…

传送门:D. Monopole Magnets 这一场也是很神奇了,先是推迟三天,后是评测鸡崩了,unrated... 题意:每一行,每一列必须都要至少有一个s,n要可以到所有的黑格,n的上下左右如果有一个s,他就可以往那个方向移动一格,n最后不能在白格,求n最少的个数. 题解: 1.每一行每一列如果有#,#必须是连续的,否则输出-1 2.如果有一行没有#,那么至少有一列要没有#,s就可以放在交点处,否则输出-1. 3.求解连通块的个数 1 #include<bits/stdc++.h> 2…

link:http://codeforces.com/contest/344/problem/A 这道题目很简单. 把输入的01 和10 当做整数,如果相邻两个数字相等的话,那么就属于同一组,否则,就新增加了一组. #include <cstdio> #include <cstdlib> #include <cstring> using namespace std; int main(void) { #ifndef ONLINE_JUDGE freopen("…

这次比赛出的题真是前所未有的水!只用了一小时零十分钟就过了前4道题,不过E题还是没有在比赛时做出来,今天上午我又把E题做了一遍,发现其实也很水.昨天晚上人品爆发,居然排到Rank 55,运气好的话没准能领到T-shirt.除此之外,锁上程序之后,看到一个人数组开小了,我还提交了一个大数据,成功Hack了一次,然后Room排名顿时升到第1. My submissions     # When Who Problem Lang Verdict Time Memory 4474604 Sep 15,…

ActiveQt Examples Using ActiveX from Qt applications. Animation Framework Examples Doing animations with Qt. Animated Tiles…

Projects typically involve many dynamic aspects, yet they're often constrained by finite conditions. These contradictory forces make it very difficult to determine with pinpoint accuracy the time and effort required. By using a set of proactive estim…