作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 set 位运算 日期 题目地址:https://leetcode.com/problems/maximum-product-of-word-lengths/description/ 题目描述 Given a string array words, find the maximum value of length(word[i]) * length(w…

传送门 318. Maximum Product of Word Lengths My Submissions QuestionEditorial Solution Total Accepted: 19855 Total Submissions: 50022 Difficulty: Medium Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two…

题目描述: Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. E…

https://leetcode.com/problems/maximum-product-of-word-lengths/ Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lo…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…

题目大意:给出一些字符串,找出两个不同的字符串之间长度之积的最大值,但要求这两个字符串之间不能拥有相同的字符.(字符只考虑小写字母). 题目分析:字符最多只有26个,因此每个字符串可以用一个二进制数来表示它含有哪些字符. 代码如下: class Solution { public: int maxProduct(vector<string>& words) { int maxn=0; int *Bit=new int[words.size()]; fill(Bit,Bit+words.…

先介绍下本题的题意: 在一个字符串组成的数组words中,找出max{Length(words[i]) * Length(words[j]) },其中words[i]和words[j]中没有相同的字母,在这里字符串由小写字母a-z组成的. 对于这道题目我们统计下words[i]的小写字母a-z是否存在,然后枚举words[i]和words[j],找出max{Length(words[i]) * Length(words[j]) }. 小写字母a-z是26位,一般统计是否存在我们要申请一个bool…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…

Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…