//克鲁斯卡尔(最小生成树) #include<cstdio> #include<iostream> #include<algorithm> using namespace std; ; int n, t; struct node { int bagin, end, len; }arr[maxn]; int fa[maxn]; void init() { ; i <= n; i++) { fa[i] = i; } } bool cmp(node a, node b…
Problem Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and B…
嘎唔!~又一次POJ过了HDU错了...不禁让我想起前两天的的Is it a tree?   orz..这次竟然错在HDU一定要是多组数据输入输出!(无力吐槽TT)..题目很简单,炒鸡水! 题意: 告诉你每个村庄之间的距离,和几组已经联通的村庄,求使所有村庄联通所要建的道路的最短距离. 很简单,用最小生成树的Prim算法,相当于邻接矩阵已知,把已联通的村庄之间的距离改为零即可. 附上AC代码: #include <stdio.h> #include <string.h> #incl…
Constructing Roads 题目链接: http://acm.hust.edu.cn/vjudge/contest/124434#problem/D Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two villa…
Constructing Roads Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road betw…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14172    Accepted Submission(s): 5402 Problem Description There are N villa…
Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13995    Accepted Submission(s): 5324 Problem Description There are N villages, which are numbered from 1 to N, and you should…
Constructing Roads Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 274 Accepted Submission(s): 172   Problem Description There are N villages, which are numbered from 1 to N, and you should build…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 题解: 纯最小生成树,只是有些边已经确定了要加入生成树中,特殊处理一下这些边就可以了. kruskal算法: 由于有些边已经确定,所以在调用kruskal()之前,就把这条边的两个顶点放在一个集合就可以了. #include<cstdio>//hdu1102 最小生成树 kruskal #include<algorithm> #define N 110 using namespa…
Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and B, or the…