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https://www.bnuoj.com/bnuoj/problem_show.php?pid=51640 dp[i][j]表示前j个数,分成了i组,最小需要多少精力. 那么,求解订票dp[i][j]的时候,要么,第i组不做题,要么,第i组做1题.2题.3题....j题 先把数组排好序.然后暴力 dp[i][j] = dp[i - 1][j] //第i组不做题. 然后枚举一个k,表示[K.....j]是第i组做的题.那么就是dp[i - 1][k - 1] + (a[j] - a[k])^2…
传送门 题意 将n个数分成m个集合,\(V_i表示max(x-y),x,y∈第\)i个集合,\(求minΣV_i\) 分析 我们先对难度排序,令dp[i][j]表示前i个数分成j个集合的最小费用 转移方程为 \[dp[i][j]=min(dp[k][j-1]+(a[i]-a[k+1])^2,dp[i][j])\] 预处理dp[i][i],dp[i][1],开 long long 吐槽 开lld过,开I64d wa,用线段树可以达到\(O(n^2)\) 类似题目:Codeforces Round…
跟 UVa 1474 - Evacuation Plan 一个题,但是在杭电上能交过,在UVa上交不过……不知道哪里有问题…… 将施工队位置和避难所位置排序. dp[i][j] 代表前 i 个避难所收留前 j 个施工队. dp[i][j] = min( dp[i - 1][j - 1], dp[i][j - 1] ) + abs( b[i] - a[j] ); 内存卡的比较死,要用滚动数组,并且记录路径的path[i][j]只能用bool型.MLE了四五次OTL…… #include <cstd…
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Greg's Workout time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was n integers a1, a2, ..., an. Th…
这题是今天下午BNU SUMMER TRAINING的C题 是队友给的解题思路,用拓扑排序然后就可以了 最后是3A 其中两次RE竟然是因为: scanf("%d",mm); ORZ 以后能用CIN还是CIN吧 QAQ 贴代码了: #include <stdio.h> #include <string.h> #include <stdlib.h> #include <math.h> #include <iostream> #in…
For the record number of American runners who completed an official race event last year, the questions often start not long after they cross the finish line: 'What's my next challenge?' and 'How much further can I push myself?' But data show that th…
A. Equator time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Polycarp has created his own training plan to prepare for the programming contests. He will train for nn days, all days are numbe…
Debugging a SQL Server query with WinDbg May 13, 2014 · Klaus Aschenbrenner · 5 Comments (Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan - you get a weekly email packed with all the essential knowledge you need to know about…