XMU 1040 Schedule 【拓扑排序】

【XMU 1040 Schedule 【拓扑排序】】的更多相关文章

XMU 1040 Schedule 【拓扑排序】

1040: Schedule Time Limit: 500 MS Memory Limit: 64 MBSubmit: 12 Solved: 2[Submit][Status][Web Board] Description Resently, loneknight is doing research on job shop schedule problem(JSP for short). Let us take a look at JSP, there are n jobs and m m…

LeetCode 210. Course Schedule II(拓扑排序-求有向图中是否存在环)

和LeetCode 207. Course Schedule(拓扑排序-求有向图中是否存在环)类似. 注意到.在for (auto p: prerequistites)中特判了输入中可能出现的平行边或自环. 代码: class Solution { public: vector<int> findOrder(int numCourses, vector<pair<int, int>>& prerequisites) { // [0, {1, 2, 3}], me…

LeetCode 207. Course Schedule（拓扑排序）

题目 There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the total number of courses and…

2-sat 输出任意一组可行解&拓扑排序+缩点 poj3683

Priest John's Busiest Day Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 8170 Accepted: 2784 Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old le…

Poj 3683-Priest John's Busiest Day 2-sat,拓扑排序

Priest John's Busiest Day Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 8872 Accepted: 3027 Special Judge Description John is the only priest in his town. September 1st is the John's busiest day in a year because there is an old le…

LeetCode编程训练 - 拓扑排序(Topological Sort)

拓扑排序基础拓扑排序用于解决有向无环图(DAG,Directed Acyclic Graph)按依赖关系排线性序列问题,直白地说解决这样的问题:有一组数据,其中一些数据依赖其他,问能否按依赖关系排序(被依赖的排在前面),或给出排序结果. 最常用解决拓扑排序问题的方法是Kahn算法,步骤可以概括为: . 根据依赖关系,构建邻接矩阵或邻接表.入度数组 . 取入度为0的数据(即不依赖其他数据的数据),根据邻接矩阵/邻接表依次减小依赖其的数据的入度 . 判断减小后是否有新的入度为0的数据,继续进行第2…

拓扑排序 Topological Sort

2018-05-02 16:26:07 在计算机科学领域,有向图的拓扑排序或拓扑排序是其顶点的线性排序,使得对于从顶点u到顶点v的每个有向边uv,u在排序中都在v前.例如,图形的顶点可以表示要执行的任务,并且边缘可以表示一个任务必须在另一个任务之前执行的约束; 在这个应用中,拓扑排序只是一个有效的任务顺序. 如果且仅当图形没有定向循环,即如果它是有向无环图(DAG),则拓扑排序是可能的. 任何 DAG 具有至少一个拓扑排序,并且已知这些算法用于在线性时间内构建任何 DAG 的拓扑排序. u {\…