传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6343 Problem L. Graph Theory Homework Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1536    Accepted Submission(s): 830 Problem Description Ther…

题意: 给定n个点,每个点有权值a[i],从A走到B的花费是下取整sqrt(a[i]-a[j]),求从1号点走到n号点的最小花费 1<=n,a[i]<=1e5 思路: #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<iostream> #include<algorithm> #include<map> #i…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6343 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Problem DescriptionThere is a complete graph containing n vertices, the weight of the i-th vertex is wi.The length…

6343.Problem L. Graph Theory Homework 官方题解: 一篇写的很好的博客: HDU 6343 - Problem L. Graph Theory Homework - [(伪装成图论题的)简单数学题] 代码: //1012-6343-数学 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<bitset&g…

Source: Connected Brain Figure above: Bullmore E, Sporns O. Complex brain networks: graph theoretical analysis of structural and functional systems.[J]. Nature Reviews Neuroscience, 2009, 10(3):186-198. Graph measures A graph G consisting of a set of…

The Beginning of the Graph Theory 是的,这不是一道题.最近数论刷的实在是太多了,我要开始我的图论与树的假期生活了. 祝愿我吧??!ShuraK...... poj1847 poj1125 neooj1339 neooj1374 neooj1574 neooj1497 poj1251 poj1789 poj2421(实现给出几条边,求最小生成树) poj2031(空间内n个球,代价是球心距-半径和,求最小生成树) jdoj1588(tarjan裸题) jdoj10…

Sasha and Interesting Fact from Graph Theory n 个 点形成 m 个有标号森林的方案数为 F(n, m) = m * n ^ {n - 1 - m} 然后就没啥难度了... #include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #defin…

CF1109D Sasha and Interesting Fact from Graph Theory 这个 \(D\) 题比赛切掉的人基本上是 \(C\) 题的 \(5,6\) 倍...果然数学计数问题比数据结构更受欢迎... 以下大致翻译自官方题解. 枚举 \(a\to b\) 路径上边的数目,记为 \(edges\) . 先来考虑给定的两个点路径上的 \(edges-1\) 个点(不含 \(a,b\) )和 \(edge\) 条边. 节点有\(edges-1\)个,顺序不同则最后的树不同…

Graph Theory                                                                 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)                                                                                        …

Codeforces 1109D. Sasha and Interesting Fact from Graph Theory 解题思路: 这题我根本不会做,是周指导带飞我． 首先对于当前已经有 \(m\) 个联通块的有标号生成树的数量是 \[ n^{m-2}\prod_{i=1}^msize_i \] 其中 \(size_i\) 是第 \(i\) 个联通块的大小． 原理就是考虑 \(prufer\) 编码,先把每个联通块看成一个点,那么序列中每出现一个第 \(i\) 联通块缩成的点,能连的边的数…