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【Longest Palindromic Substring】cpp

题目: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 代码: class Solution { public: string longestPalindrome(string s) { const…

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【JAVA、C++】LeetCode 005 Longest Palindromic Substring

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 解题思路一: 暴力枚举 共N^2量级个子串(从下标零开始),每次检查需一个for循环,等于是3重for循环,时间复杂度O(n^3) 解题思路二: 动态…

【LeetCode】Longest Palindromic Substring 解题报告

DP.KMP什么的都太高大上了.自己想了个朴素的遍历方法. [题目] Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. [思路](应该算是O(n)吧) 从中间向两端搜索.分别找到以每一个字母为中心的最…

【leedcode】 Longest Palindromic Substring

Given a , and there exists one unique longest palindromic substring. https://leetcode.com/problems/longest-palindromic-substring/ 求最大回文的长度,其实这道题比上一道有意思. 方法1 循环查询 (该方案为O(N*N*N)) public static boolean isPalindrome(String s, int start, int end) { if (((…

【LeetCode】5. Longest Palindromic Substring 最大回文子串

题目: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 思路:用Manacher算法得到最大回文子串的长度,得到带#的最大回文子串,用split剔除#后转化成String形式输出即可. public…

【leetcode】5. Longest Palindromic Substring

题目描述: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 解题分析: 之前百度实习生面试也被问到这个问题.这个题比较简单.就是在分别考虑对称字符字串为奇数和偶数的情况,在不超过字符串范围的情况下向…

【leetcode】Longest Palindromic Substring (middle) 经典

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 动态规划解法 O(n2) 超时 string longestPalindrome(string s) { if(s.empty()) return s…