Closest Common Ancestors Time Limit: 2000MS   Memory Limit: 10000K Total Submissions: 15446   Accepted: 4944 Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines the…

POJ 1470 Closest Common Ancestors(最近公共祖先 LCA) Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines the closest common ancestor of u and v in the tree. The closest co…

Closest Common Ancestors Time Limit: 2000MS   Memory Limit: 10000K Total Submissions: 13372   Accepted: 4340 Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines the…

Closest Common Ancestors Time Limit: 2000MS   Memory Limit: 10000K Total Submissions: 13370   Accepted: 4338 Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines the…

Closest Common Ancestors Time Limit: 10 Seconds      Memory Limit: 32768 KB Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines the closest common ancestor of u and v in the tr…

任意门:http://poj.org/problem?id=1470 Closest Common Ancestors Time Limit: 2000MS   Memory Limit: 10000K Total Submissions: 22519   Accepted: 7137 Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pa…

传送门 Closest Common Ancestors Time Limit: 2000MS   Memory Limit: 10000K Total Submissions: 14915   Accepted: 4745 Description Write a program that takes as input a rooted tree and a list of pairs of vertices. For each pair (u,v) the program determines…

1.输出测试用例中是最近公共祖先的节点,以及这个节点作为最近公共祖先的次数. 2.最近公共祖先,离线Tarjan算法 3. /* POJ 1470 给出一颗有向树,Q个查询 输出查询结果中每个点出现次数 */ /* 离线算法,LCATarjan 复杂度O(n+Q); */ #include<iostream> #include<stdio.h> #include<string.h> using namespace std; ; ;//查询数的最大值 //并查集部分 in…

Tarjan算法的详细介绍,请戳: http://www.cnblogs.com/chenxiwenruo/p/3529533.html #include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> #include <string> #include <vector> /* AC 一开始读取数据的方式并不好,运行900多ms. 后来参照…

LCA思想:http://www.cnblogs.com/hujunzheng/p/3945885.html 在求解最近公共祖先为问题上,用到的是Tarjan的思想,从根结点开始形成一棵深搜树,非常好的处理技巧就是在回溯到结点u的时候,u的子树已经遍历,这时候才把u结点放入合并集合中,这样u结点和所有u的子树中的结点的最近公共祖先就是u了,u和还未遍历的所有u的兄弟结点及子树中的最近公共祖先就是u的父亲结点.以此类推..这样我们在对树深度遍历的时候就很自然的将树中的结点分成若干的集合,两个集合中…