B. Painting The Wall time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output User ainta decided to paint a wall. The wall consists of n2 tiles, that are arranged in an n × n table. Some tiles are p…

B. Painting The Wall time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output User ainta decided to paint a wall. The wall consists of n2 tiles, that are arranged in an n × n table. Some tiles are p…

                                                                               D. Painting The Wall   User ainta decided to paint a wall. The wall consists of n2 tiles, that are arranged in an n × n table. Some tiles are painted, and the others are n…

题意:有一个 $n * n$ 的网格,其中 $m$ 个格子上涂了色.每次随机选择一个格子涂色,允许重复涂,求让网格每一行每一列都至少有一个格子涂了色的操作次数期望.题解:,,这种一般都要倒推才行.设$f[i][j]$表示还有$i$行,$j$列未满足的情况下的期望次数.因为每次选择都是完全随机,不受其他东西的影响.所以对于题中给出的$m$,实际上就是告诉了我们要求什么东西,假设在已经有那$m$个涂色方块的情况下,我们还有$t1$行,$t2$列未满足,那么我们要求的就是$f[t1][t2]$.那么我…

http://codeforces.com/problemset/problem/399/D 题意:给出n和m,表示在一个n*n的平面上有n*n个方格,其中有m块已经涂色.现在随机选中一块进行涂色(如果已经涂色跳过,也消耗时间),消耗1个步骤.终止条件为每行每列都有至少有一块瓷砖被涂色.问说涂成满意的情况需要时间的期望. 思路:把整个方格分成四部分,如果选择左上角上的一块,那么行和列都将被涂上一个:右上角的话,行被涂上一个,列不变:左下角的话,行不变,列被涂上一个:右下角,行列都不变. 状态转移…

题目大意:一个$n\times n$的棋盘,其中有$m$个格子已经被染色,执行一次染色操作(无论选择的格子是否已被染色)消耗一个单位时间,染色时选中每个格子的概率均等,求使每一行.每一列都存在被染色的格子的期望用时. 传送门 显然,被染色的砖的位置对解题是没有影响的,我们可以将已染色砖所在的行和列移动到右下角,问题就转化到了在更小棋盘中的新问题. 在任一时刻,棋盘内的状态如下: 其中绿色区域为当前问题的棋盘,选中对行和列都有贡献: 选中黄色对行或列有贡献: 选中红色没有贡献: 设$f[i][j]…

23333,还是不会..%%%http://hzwer.com/6276.html #include <bits/stdc++.h> #define LL long long #define lowbit(x) x&(-x) #define inf 0x3f3f3f3f using namespace std; inline int ra() { ,f=; char ch=getchar(); ; ch=getchar();} +ch-'; ch=getchar();} return…

Problem Description As a amateur artist, Xenocide loves painting the wall. The wall can be considered as a line consisting of n nodes. Each node has its own color. Xenocide spends all day in front of the wall. Sometimes, he paints some consecutive no…

Paint The Wall Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3427    Accepted Submission(s): 955 Problem Description As a amateur artist, Xenocide loves painting the wall. The wall can be c…

Being a good developer is like being any other good professional, it’s all it’s about doing as much quality work as possible. There is a popular sentence that summarises it: “Do it. Do it right. Do it right now”. 1.- Have your own to do list for the…

总体感觉这次出的题偏数学,数学若菜表示果断被虐.不过看起来由于大家都被虐我2题居然排到331,rating又升了74.Div2-AA. The Walltime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputIahub and his friend Floyd have started painting a wall. Iahub is paintin…

这是 meelo 原创的 IEEEXtreme极限编程比赛题解 Xtreme 10.0 - Painter's Dilemma 题目来源 第10届IEEE极限编程大赛 https://www.hackerrank.com/contests/ieeextreme-challenges/challenges/painters-dilemma Bob just got his first job as a house painter. Today, on his first day on the jo…

python中的装饰器主要用于在已有函数实现功能前附加需要输出的信息,下面将用实例展示我如何写装饰器. 首先分别尝试写装饰器装饰一个无参函数和一个有参函数(被装饰函数仅输出,无返回值情况下) def my_log(func): def wrapper(): print('decorator works') func() return wrapper #返回的只是wrapper函数对象,此时并没有运行 @my_log def run(): # run=my_log(run)=wrapper 返回的…

Paint The Wall Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3114    Accepted Submission(s): 846 Problem Description As a amateur artist, Xenocide loves painting the wall. The wall can be co…

Codeforces Round #198 (Div. 2) 昨天看到奋斗群的群赛,好奇的去做了一下, 大概花了3个小时Ak,我大概可以退役了吧 那下面来稍微总结一下 A. The Wall Iahub and his friend Floyd have started painting a wall. Iahub is painting the wall red and Floyd is painting it pink. You can consider the wall being mad…

题目链接: Wall Painting Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2681    Accepted Submission(s): 857 Problem Description Ms.Fang loves painting very much. She paints GFW(Great Funny Wall) ev…

Wall Painting Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1026    Accepted Submission(s): 280 Problem Description Ms.Fang loves painting very much. She paints GFW(Great Funny Wall) every da…

Wall Painting Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4339    Accepted Submission(s): 1460 Problem Description Ms.Fang loves painting very much. She paints GFW(Great Funny Wall) every…

题目链接 下午比赛的时候没有想出来,其实就是int型的数分为30个位,然后按照位来排列枚举. 题意:求n个数里面,取i个数异或的所有组合的和,i取1~n 分析: 将n个数拆成30位2进制,由于每个二进制位异或后相加和原来的数异或相加是一样的,所以只需要对每一位累加计算,用组合数学取数就行了,奇数个异或得1,偶数个异或得0,再乘以自己的二进制位值,复杂度O(30*n*n) #include <iostream> #include <cstdio> #include <cmath…

题意: 从给出的颜料中选出天数个,第一天选一个,第二天选二个... 例如:第二天从4个中选出两个,把这两个进行异或运算(xor)计入结果 对于每一天输出所有异或的和 $\sum_{i=1}^nC_{n}^{i}$ 思路: 0⊕0=0,1⊕0=1,0⊕1=1,1⊕1=0(同为0,异为1) 例如样例 4 1 2 10 1 这4个数的二进制表示分别为: 0 0 0 1 0 0 1 0 1 0 1 0 0 0 0 1 第一天: 分别选出 1, 2, 10 ,1 = 14 第二天: 从4个中选出2个进行异…

Problem Description Sakura has a very magical tool to paint walls. One day, kAc asked Sakura to paint a wall that looks like an M×N matrix. The wall has M×N squares in all. In the whole problem we denotes (x,y) to be the square at the x-th row, y-th…

Python MOOC 翻Wall和互联网编程的那些事 声明: 1)本报告由博客园bitpeach撰写,版权所有,免费转载,请注明出处,并请勿作商业用途. 2)若本文档内有侵权文字或图片等内容,请联系作者bitpeach删除相应部分. 3)本文档内容涉及主题在引言中提及.仅仅作为参考用途,抛砖引玉,不作为证据证明用途,请自行取舍,核实引用. 目录 0引言    1 1 Python的那些事    2 1.1Python的安装思路与简要介绍    2 1.1.1 Python安装思路    2 1…

D - Joyful Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Sakura has a very magical tool to paint walls. One day, kAc asked Sakura to paint a wall that looks like an $M \times N$ matrix. The wal…

链接: https://vjudge.net/problem/HDU-4810 题意: Ms.Fang loves painting very much. She paints GFW(Great Funny Wall) every day. Every day before painting, she produces a wonderful color of pigments by mixing water and some bags of pigments. On the K-th day…

Paint on a Wall Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 830    Accepted Submission(s): 325 Problem Description Annie wants to paint her wall to an expected pattern. The wall can be repr…

题目 题目描述 gx和lc去参加noip初赛,其中有一种题型叫单项选择题,顾名思义,只有一个选项是正确答案.试卷上共有n道单选题,第i道单选题有ai个选项,这ai个选项编号是1,2,3,-,ai,每个选项成为正确答案的概率都是相等的.lc采取的策略是每道题目随机写上1-ai的某个数作为答案选项,他用不了多少时间就能期望做对 道题目.gx则是认认真真地做完了这n道题目,可是等他做完的时候时间也所剩无几了,于是他匆忙地把答案抄到答题纸上,没想到抄错位了:第i道题目的答案抄到了答题纸上的第i+1道题目…

Description Once upon a time there was a greedy King who ordered his chief Architect to build a wall around the King's castle. The King was so greedy, that he would not listen to his Architect's proposals to build a beautiful brick wall with a perfec…

3143: [Hnoi2013]游走 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 2264  Solved: 987[Submit][Status][Discuss] Description 一个无向连通图,顶点从1编号到N,边从1编号到M. 小Z在该图上进行随机游走,初始时小Z在1号顶点,每一步小Z以相等的概率随机选 择当前顶点的某条边,沿着这条边走到下一个顶点,获得等于这条边的编号的分数.当小Z 到达N号顶点时游走结束,总分为所有获得的分数…

这道题之前我写过一个巨逗比的写法(传送门:http://www.cnblogs.com/liu-runda/p/6220381.html) 当时的原因是这道题可以抽象出和"绿豆蛙的归宿"差不多的模型,而我之前写"绿豆蛙的归宿"就是用的这个巨逗比的方法. 然后前几天看了@Sengxian的博客里"绿豆蛙的归宿"的写法(传送门:https://blog.sengxian.com/algorithms/probability-and-expected-…

(转)http://blog.csdn.net/u013081425/article/details/39240021 http://acm.hdu.edu.cn/showproblem.php?pid=4418 读了一遍题后大体明白意思,但有些细节不太确定.就是当它处在i点处,它有1~m步可以走,但他走的方向不确定呢.后来想想这个方向是确定的,就是他走到i点的方向,它会继续朝着这个方向走,直到转向回头. 首先要解决的一个问题是处在i点处,它下一步该到哪个点.为了解决方向不确定的问题,将n个点转…