PHP判断两个矩形是否相交】的更多相关文章

<?php $s = is_rect_intersect(1,2,1,2,4,5,0,3); var_dump($s); /* 如果两个矩形相交,那么矩形A B的中心点和矩形的边长是有一定关系的. Case 2345中,两个中心点间的距离肯定小于AB边长和的一半. Case 1中就像等了. 设A[x01,y01,x02,y02]  B[x11,y11,x12,y12]. 矩形A和矩形B物理中心点X方向的距离为Lx:abs( (x01+x02)/2 – (x11+x12) /2) 矩形A和矩形B物…
源代码 public bool JudgeRectangleIntersect(double RecAleftX, double RecAleftY, double RecArightX, double RecArightY, double RecBleftX, double RecBleftY, double RecBrightX, double RecBrightY) { bool isIntersect = false; try { double zx = getAbsluteValue(…
Description Given a rectangle and a circle in the coordinate system(two edges of the rectangle are parallel with the X-axis, and the other two are parallel with the Y-axis), you have to tell if their borders intersect. Note: we call them intersect ev…
题目链接:https://vjudge.net/problem/POJ-1410 题意:判断线段和矩形是否相交. 思路:注意这里的相交包括线段在矩形内,因此先判断线段与矩形的边是否相交,再判断线段的两端点是否在矩形内(因为是矩形,即凸多边形,直接用叉积判断即可,如果是一般的多边形,需要用射线法判断.) AC code: #include<cstdio> #include<algorithm> #include<cmath> #include<cstdlib>…
SQL中常常要判断两个时间段是否相交,该如何判断呢?比如两个时间段(S1,E1)和(S2,E2).我最先想到的是下面的方法一.方法一:(S1 BETWEEN S2 AND E2) OR (S2 BETWEEN S1 AND E1).很好理解:一个时间段的开始时间S1在另一个时间中间(S2,E2),或者开始时间S2在另一个时间中间(S1,E1),这个方法比较繁琐 方法二:本方法先考虑这两段时间什么情况下不相交,如图:    -----+-----------------+-------------…
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1221 Rectangle and Circle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3434    Accepted Submission(s): 904 Problem Description Given a rectangle…
C. White Sheet There is a white sheet of paper lying on a rectangle table. The sheet is a rectangle with its sides parallel to the sides of the table. If you will take a look from above and assume that the bottom left corner of the table has coordina…
直接上代码,过程不复杂 /// <summary> /// 判断两条线是否相交 /// </summary> /// <param name="a">线段1起点坐标</param> /// <param name="b">线段1终点坐标</param> /// <param name="c">线段2起点坐标</param> /// <param…
bool GraphicsUtil::linesCross(b2Vec2 v0, b2Vec2 v1, b2Vec2 t0, b2Vec2 t1, b2Vec2 &intersectionPoint) { if ( areVecsEqual(v1,t0) || areVecsEqual(v0,t0) || areVecsEqual(v1,t1) || areVecsEqual(v0,t1) ) return false; b2Vec2 vnormal = v1 - v0; vnormal = b…
Given two rectangles, find if the given two rectangles overlap or not. A rectangle is denoted by providing the x and y co-ordinates of two points: the left top corner and the right bottom corner of the rectangle. Note that two rectangles sharing a si…