题目链接:https://vjudge.net/problem/HDU-3709 Balanced Number Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 6615    Accepted Submission(s): 3174 Problem Description A balanced number is a non-nega…

Balanced Number Problem Description A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box with weight indicated by the digit. When a pivot is placed at some…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3709 题目大意就是求给定区间内的平衡数的个数 要明白一点:对于一个给定的数,假设其位数为n,那么可以有n个不同的位作为支点,但每次只能有一个支点 定义dp[len][pos][k],len表示当前还需处理的位数,pos表示当前的所选的支点的位置,k表示计算到当前的力矩之和(即从最高位到第len+1位) 容易知道如果在某一个len>1的位置k已经小于0,那么就可以直接剪枝 代码如下 : #includ…

Problem Description A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box with weight indicated by the digit. When a pivot is placed at some digit of the nu…

Balanced Number Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 3798    Accepted Submission(s): 1772 Problem Description A balanced number is a non-negative integer that can be balanced if a pi…

A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box with weight indicated by the digit. When a pivot is placed at some digit of the number, the distance f…

题意: 给出求ab之间有多少个平衡数   4139为平衡数   以3为轴   1*1+4*2==9*1 思路很好想但是一直wa  : 注意要减去前导零的情况 0 00 000 0000   不能反复计算 #include<bits/stdc++.h> using namespace std; //input by bxd #define rep(i,a,b) for(int i=(a);i<=(b);i++) #define repp(i,a,b) for(int i=(a);i>…

[HDU3709]Balanced Number 试题描述 A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box with weight indicated by the digit. When a pivot is placed at some digit…

// 多校5 HDU5787 K-wolf Number 数位DP // dp[pos][a][b][c][d][f] 当前在pos,前四个数分别是a b c d // f 用作标记,当现在枚举的数小于之前的数时,就不用判断i与dig[pos]的大小 // 整体来说就,按位往后移动,每次添加后形成的数都小于之前的数,并且相邻k位不一样,一直深搜到cnt位 // http://blog.csdn.net/weizhuwyzc000/article/details/52097690 // #prag…

 Balanced Number Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description A balanced number is a non-negative integer that can be balanced if a pivot is placed at some digit. More specifically, imagine each digit as a box wi…