类似phonelist  一次ac 判断失败主要有两个要点 1. 是否包含了某段的结尾结点   说明某段被此段包含 2.此段的结尾结点是否为某段的痕迹   说明此段被包含 #include<bits/stdc++.h> using namespace std; ][]; ]; ; bool insert1( char *word ) { ; ;i<strlen(word);i++) { '; ) trie[root][ ch ]=++pos; &&root!=)retur…

Immediate Decodability An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that no two codes within a…

巧了,昨天刚刚写了个字典树,手到擒来,233. Problem Description An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that n…

吐槽下我的渣渣英语啊,即使叫谷歌翻译也没有看懂,最后还是自己读了好几遍题才读懂. 题目大意:题意很简单,就是给一些互不相同的由'0','1'组成的字符串,看看有没有一个字符串是否会成为另一个的开头的子串. 直接简单粗暴的去比较就可以了. 这是原题:   Immediate Decodability  An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is th…

Immediate Decodability Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1378    Accepted Submission(s): 706 Problem Description An encoding of a set of symbols is said to be immediately decodabl…

Immediate Decodability Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2248    Accepted Submission(s): 1168点我 Problem Description An encoding of a set of symbols is said to be immediately decoda…

UVA644 Immediate Decodability Trie Trie模板题 难度几乎相等的题P2580 于是他错误的点名开始了 对于每组数据都清空树太浪费时间,所以我们只要在需要新点时预先把新点原有的数据清空即可. 剩下除了一些细节要注意,没啥要说的了 (luogu的标签系统有些迷啊) #include<iostream> #include<cstdio> #include<cstring> using namespace std; struct data{…

题目来源:http://poj.org/problem?id=1056   http://poj.org/problem?id=3630 两题非常类似,所以在这里一并做了. 1056题目大意: 如果一组编码中不存在一个编码是另一个编码的前缀的情况,我们就称这组编码是“可立即解码的”(immediately decodable).我们假定编码都是二进制的,一组编码中没有相同的码.每个编码长度都不超过10,每组编码数目都在2到8之间. 比如,一组二进制编码:{A, B, C, D},其中:A: 01…

题意:一个码如果是另一个码的前缀,则 is not immediately decodable,不可直接解码,也就是给一串二进制数字给你,你不能对其解码,因解码出来可能有多种情况. 思路:将每个码按长度从短到长排序,逐个与其后面的码比较,若前面相同位数完全一样了,那就可以输出了. #include <iostream> #include <stdio.h> #include <string> #include <map> #include <cstri…

题意翻译 本题有多组数据.每组数据给出一列以"9"结尾的仅包含'0'和'1'的字符串,如果里面有一个是另一个的子串,输出"Set &case is not immediately decodable",否则输出"Set &case is immediately decodable".换行. case从1开始计数. 感谢@Fuko_Ibuki 提供的翻译 题目描述 PDF 输入输出格式 输入格式: 输出格式: 输入输出样例 输入样例…