leetcode - 53. Maximum Subarray - Easy descrition Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has th…

原题 Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. Follow up:…

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. Follow up: If…

53. 最大子序和 53. Maximum Subarray 题目描述 给定一个整数数组 nums,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和. LeetCode53. Maximum Subarray 示例: 输入: [-2,1,-3,4,-1,2,1,-5,4], 输出: 6 解释: 连续子数组 [4,-1,2,1] 的和最大,为 6. 进阶: 如果你已经实现复杂度为 O(n) 的解法,尝试使用更为精妙的分治法求解. Java 实现 class Solution…

53. Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has the largest sum = 6. 思路:这个题还挺经典…

Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] has the largest sum = 6. click to show more practice. Mor…

题目描述 给定一个序列(至少含有 1 个数),从该序列中寻找一个连续的子序列,使得子序列的和最大. 例如,给定序列 [-2,1,-3,4,-1,2,1,-5,4], 连续子序列 [4,-1,2,1] 的和最大,为 6. 扩展练习: 若你已实现复杂度为 O(n) 的解法,尝试使用更为精妙的分治法求解. 思路 思路一: maxSum 必然是以numsi结尾的某段构成的,也就是说maxSum的candidate必然是以nums[i]结果的.如果遍历每个candidate,然后进行比较,那么就能找到最大…

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. 这个题目思路跟[LeetC…

思路:nums为给定的数组,动态规划: 设 一维数组:dp[i] 表示 以第i个元素为结尾的一段最大子序和. 1)若dp[i-1]小于0,则dp[i]加上前面的任意长度的序列和都会小于nums[i],则 dp[i] = nums[i]; 2)  若dp[i-1] 不小于0, 则 dp[i] = dp[i-1] + nums[i]; 边界条件:dp[0] = nums[0]  (nums数组的第一个元素的最大长度就是本身) class Solution { public: int maxSubAr…

1. 原题链接 https://leetcode.com/problems/maximum-subarray/discuss/ 2. 题目要求 给定一个整型数组,返回其子串之和的最大值 例如,[-2,1,-3,4,-1,2,1,-5,4]中,[4,-1,2,1]可以构成最大子串之和6 3. 解题思路 对数组进行一次遍历,每次加入一个元素前,先判断其加入后累加和与该元素的大小,取最大者.然后每遍历一个元素,选取当前的最大子串之和. 4. 代码实现 public class MaximumSubar…