Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5…

Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,…

题意 Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,6]…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

题意: 给一个升序的数组,如果target在里面存在了,返回其下标,若不存在,返回其插入后的下标. 思路: 来一个简单的二分查找就行了,注意边界. class Solution { public: int searchInsert(vector<int>& nums,int target) { , R=nums.size(); while(L<R) { )/; if(nums[mid]>=target) R=mid; ; } return R; } }; AC代码…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

题目意思:在递增数组中找到目标数的位置,如果目标数不在数组中,返回其应该在的位置. 思路:折半查找,和相邻数比较,注意边界 class Solution { public: int searchInsert(vector<int>& nums, int target) { ,end=nums.size()-; ; while(start<=end){ flag=(start+end)/; if(nums[flag]==target)return flag; else if(num…

Description: Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

问题描述:给定一个有序序列,如果找到target,返回下标,如果找不到,返回插入位置. 算法分析:依旧利用二分查找算法. public int searchInsert(int[] nums, int target) { return binarySearch(nums, 0, nums.length - 1, target); } public int binarySearch(int[] nums, int left, int right, int target) { int mid = (…