LeetCode 5_Longest Palindromic Substring  题目描写叙述: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 也即:求字符串中最长回文子串. 回文是什么我就不多…

题目: Given a , and there exists one unique longest palindromic substring. 解题思路:1.简单思路:暴力破解法,时间复杂度O(n^3),肯定通不过. 2.动态规划法:(一般含“最XX”等优化词义的题意味着都可以动态规划求解),时间复杂度O(n^2),空间复杂度O(n^2). 形如"abba", "abbba"这样的字符串,如果用dp[i][j]表示从下标i到j之间的子字符串所构成的回文子串的长度,…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 这道题让我们求最长回文子串,首先说下什么是回文串,就是正读反读都一样的字符串,比如 "bob", "level", &q…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 题目的意思:输入一个字符串S,找出其最长回文串 用动态规划求解 决策变量:dp[i][j]记录从s[i]到s[j]组成的子串是否为回文. dp[i+1…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 方法: Manacher's algorithm,具体看这里http://leetcode.com/2011/11/longest-palindrom…

明天就要上课了,再过几天又要见班主任汇报项目进程了,什么都没做的我竟然有一种迷之淡定,大概是想体验一波熬夜修仙的快乐了.不管怎么说,每天还是要水一篇博文,写一个LeetCode的题才圆满. 题目:Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example:  Input: "babad" :  Out…

问题大意是在给定字符串中查找最长的回文子串,所谓的回文就是依据中间位置对称的字符串,比如abba,aba都是回文. 这个问题初一看,非常简单,但是会很快发现那些简单的思路都会带来O(n^3)级别的时间复杂度,n为传入字符串的实际长度.比如说下面的代码中的暴力枚举 for(i = 0; i < n; i = i + 1) for(j = i + 1; j < n; j = j + 1) ti = i, tj = j while(ti < tj && s[ti] == s[t…

Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Example 2: Input: "cbbd"…

题目链接 Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 求字符串的最长回文子串 算法1:暴力解法,枚举所有子串,对每个子串判断是否为回文,复杂度为O(n^3) 算法2:删除暴力解法中有很多重复的判…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 动态规划 public class Solution { public String longestPalindrome(String s) { if…