Luogu 1894 [USACO4.2]完美的牛栏The Perfect Stall / POJ 1274 The Perfect Stall(二分图最大匹配) Description 农夫约翰上个星期刚刚建好了他的新牛棚,他使用了最新的挤奶技术.不幸的是,由于工程问题,每个牛栏都不一样.第一个星期,农夫约翰随便地让奶牛们进入牛栏,但是问题很快地显露出来:每头奶牛都只愿意在她们喜欢的那些牛栏中产奶.上个星期,农夫约翰刚刚收集到了奶牛们的爱好的信息(每头奶牛喜欢在哪些牛栏产奶).一个牛栏只能容纳…

poj——1274   The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 25709   Accepted: 11429 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to e…

两题二分图匹配的题: 1.一个农民有n头牛和m个畜栏,对于每个畜栏,每头牛有不同喜好,有的想去,有的不想,对于给定的喜好表,你需要求出最大可以满足多少头牛的需求. 2.给你学生数和课程数,以及学生上的课,如果可以做到每个学生代表不同的课程并且所有的课程都被代表输出"YES"(学生能代表一门课当且仅当他上过). 1.POJ 1274 The Perfect Stall http://poj.org/problem?id=1274 和上一题过山车一样,也是二分图匹配的. 水题. #incl…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24081   Accepted: 10695 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…

题目链接:http://poj.org/problem?id=1274 题目意思:有 n 头牛,m个stall,每头牛有它钟爱的一些stall,也就是几头牛有可能会钟爱同一个stall,问牛与 stall 最大匹配数是多少. 二分图匹配,匈牙利算法入门题,留个纪念吧. 书上看到的一些比较有用的知识点: 增广:通俗地说,设当前二分图中,已有 x 个匹配边(也就是假设代码中match[i] 不为0的个数有x个),现在对 i 点(也就是代码中dfs中的参数 x) 指定一个匹配点 j, 由于 j 可能有…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 26274   Accepted: 11672 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering p…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 20874   Accepted: 9421 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering pr…

The Perfect Stall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 17768   Accepted: 8104 Description Farmer John completed his new barn just last week, complete with all the latest milking technology. Unfortunately, due to engineering pr…

题目地址:http://poj.org/problem?id=1274 把每个奶牛ci向它喜欢的畜栏vi连边建图.那么求最大安排数就变成求二分图最大匹配数. #include<cstdio> #include<iostream> #include<string.h> #include<algorithm> #include<math.h> #include<stdbool.h> #include<time.h> #incl…

题意: N头牛M个牛棚,每只牛都有它自己指定的若干个它愿意呆的牛棚. 每个牛棚最多呆一头牛. 问最多可以满足多少头牛的愿望. 思路: 裸二分图最大匹配. 代码: int n,m; vector<int> graph[205]; int cx[205],cy[205]; bool bmask[205]; int findPath(int u){ int L=graph[u].size(); rep(i,0,L-1){ int v=graph[u][i]; if(!bmask[v]){ bmask…