03-树2. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…

03-树3. Tree Traversals Again (25) 题目来源:http://www.patest.cn/contests/mooc-ds/03-%E6%A0%913 An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys num…

03-树3. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…

1086. Tree Traversals Again (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with th…

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/667 5-5 Tree Traversals Again   (25分) An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys n…

1086 Tree Traversals Again (25分)   An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations ar…

7-5 Tree Traversals Again (25 分)   An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations ar…

题目 An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations are: push(1); push(2); push(3); po…

题意:用栈的push.pop操作给出一棵二叉树的中序遍历顺序,求这棵二叉树的后序遍历. 需要一个堆结构s,一个child变量(表示该节点是其父亲节点的左孩子还是右孩子),父亲节点fa对于push v操作:1).第一个push肯定是根节点root.2).根据child变量,建立fa与v的父子关系.3).由于是中序遍历,所以接下来的节点必定是v的left(如果有的话),child=left,fa=v;4).然后进行push操作 对于pop操作:1).根据中序遍历性质,可知接下来的节点必定是pop节点…

题意:输入一个正整数N(<=30),接着输入2*N行表示栈的出入(入栈顺序表示了二叉搜索树的先序序列,出栈顺序表示了二叉搜索树的中序序列),输出后序序列. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; stack<int>st; ],b[]; ]; void build(int n,int*a,int*b,int*ans){ if(!n)…