678. Valid Parenthesis String Medium Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must…

Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must have a corresponding right parenthesi…

Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must have a corresponding right parenthesi…

[LeetCode]678. Valid Parenthesis String 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/valid-parenthesis-string/description/ 题目描述: Given a string containing only three types…

https://leetcode.com/problems/valid-parenthesis-string/description/ 这个题的难点在增加了*,*可能是(也可能是).是(的前提是:右边有多余的).是)的前提是:左边有多余的(.所以他们的位置信息是重要的. class Solution { public: bool checkValidString(string s) { // *可以是(或者), 用openMax/Min来表示最多和最少可能没有被匹配的(的数目. // openM…

题目: Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: 1.Any left parenthesis '(' must have a corresponding right pare…

Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must have a corresponding right parenthesi…

原题链接在这里:https://leetcode.com/problems/valid-parenthesis-string/description/ 题目: Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by…

Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules: Any left parenthesis '(' must have a corresponding right parenthesi…

第一种方法,用栈实现,最容易想到,也比较容易实现,每次碰到‘)’时update max_len,由于要保存之前的‘(’的index,所以space complexity 是O(n) // 使用栈,时间复杂度 O(n),空间复杂度 O(n) class Solution { public: int longestValidParentheses(string s) { , last = -; stack<int> lefts; ; i < s.size(); ++i) { if (s[i]…