题意:有n种不同的珍珠 每种珍珠的价格不同  现在给出一个采购单 标注了需要不同等级的珍珠和相对于的个数(输入按价格升序排列) 其中 价格为   (当前种类价格+10)*购买数量  这样就有一种诡异的现象,当你把购买x个 低价格珍珠的时候 可能还没有把x个低价格珍珠 换成高价格珍珠来购买 总价更便宜 同时采购上的珍珠只能低的换高的价格买 让你求最小总价 思路: 1. 不能跳跃着换  比如  价格分别为  x  x+1 x+2  不可能 x+1不动只换x到x+2买 因为如果x换到x+2买总价可以更…

Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its name because it delivers to the royal family of Pearlania. But it also produces bracelets…

1.POJ 1260 2.链接:http://poj.org/problem?id=1260 3.总结:不太懂dp,看了题解 http://www.cnblogs.com/lyy289065406/archive/2011/07/31/2122652.html 题意:珍珠,给出需求,单价,要求用最少的钱就可以买到相同数量的,相同(或更高)质量的珍珠. 把握题意,1.输入时,后输入的珍珠价格一定比前面输入的要贵.2.用高质量珍珠替代低质量. #include<iostream> #include…

http://poj.org/problem?id=1260 Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8474   Accepted: 4236 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls…

题目:http://poj.org/problem?id=1260 题意:给出几类珍珠,以及它们的单价,要求用最少的钱就可以买到相同数量的,相同(或更高)质量的珍珠. 珍珠的替代必须是连续的,不能跳跃替代(这个不难证明,因为假如用第i+2类去替代第i类珍珠,会使最终的支付价格降低,那么用第i+1类去替代第i类珍珠会使最终的支付价格更加低) #include<iostream> #include<cstdio> #include<cstring> #include<…

Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 10558   Accepted: 5489 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its…

Pearls Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7947   Accepted: 3949 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its…

思路: 直接DP也能做,这里用斜率DP. dp[i] = min{ dp[j] + ( sum[i] - sum[j] + 10 )*pr[i]} ; k<j<i  =>  dp[j] - dp[k] <pr[i]*( sum[j] - sum[k] ) 再套模板 #include<queue> #include<cstring> #include<set> #include<map> #include<stack> #i…

这个题目数据量很小,但是满足斜率优化的条件,可以用斜率优化dp来做. 要注意的地方,0也是一个决策点. #include <iostream> #include <cstdio> #include <cstring> using namespace std; const int maxn=1e2+9; int dp[maxn]; int a[maxn],p[maxn],sum[maxn]; int que[maxn]; bool chk1(int i,int j,int…

Pearls Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 6670 Accepted: 3248 Description In Pearlania everybody is fond of pearls. One company, called The Royal Pearl, produces a lot of jewelry with pearls in it. The Royal Pearl has its name…