Luogu2295 MICE】的更多相关文章

Lougu2295 MICE 给一个 \(n\times m\) 的矩阵 \(a\) ,求一条从 \((1,\ 1)\) 到 \((n,\ m)\) 的最短路径,使得与路径相接的所有网格的权值和最小 \(n,\ m\leq10^3,\ 0\leq a_{i,j}\leq100\) dp 令 \(f_{0/1,\ i,\ j}\) 表示,走到 \((i,\ j)\) 时,上一步是向下走/向右走的最优值 代码 #include <bits/stdc++.h> using namespace std…
D. Bag of mice time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The dragon and the princess are arguing about what to do on the New Year's Eve. The dragon suggests flying to the mountains t…
时间限制 30 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to…
D. Bag of mice time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The dragon and the princess are arguing about what to do on the New Year's Eve. The dragon suggests flying to the mountains t…
time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The dragon and the princess are arguing about what to do on the New Year's Eve. The dragon suggests flying to the mountains to watch fairies…
每每以为攀得众山小,可.每每又切实来到起点,大牛们,缓缓脚步来俺笔记葩分享一下吧,please~ --------------------------- 笔者寄语:缺失值是数据清洗过程中非常重要的问题(其他方法可见:R语言︱异常值检验.离群点分析.异常值处理),笔者在进行mice包的多重插补过程中遇到相当多的问题. 大致的步骤简介如下: 缺失数据集--MCMC估计插补成几个数据集--每个数据集进行插补建模(glm.lm模型)--将这些模型整合到一起(pool)--评价插补模型优劣(模型系数的t统…
1056. Mice and Rice (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. Th…
传送门 首先\(\sum c\)有些大,考虑将其缩小降低难度 考虑一个贪心:第一次所有老鼠都进入其左边第一个容量未满的洞(如果左边没有就进入右边第一个未满的洞),第二次所有老鼠都进入其右边第一个容量未满的洞(如果右边没有就进入左边第一个未满的洞),我们只保留这\(2N\)个洞,答案也不会变,因为在最优情况下老鼠最多只会进入这些洞.通过这一步,我们的\(\sum c\)降低到了\(2N\)级别. 考虑将容量为\(c\)的洞拆分为\(c\)个容量为\(1\)的洞,将老鼠和洞放在一起按照\(dis\)…
Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to become a FatMouse. First…
有n个老鼠,第一行给出n个老鼠的重量,第二行给出他们的顺序.1.每一轮分成若干组,每组m个老鼠,不能整除的多余的作为最后一组.2.每组重量最大的进入下一轮.让你给出每只老鼠最后的排名.很简单,用两个数组模拟一下即可order1存储进入当前一轮老鼠的索引顺序order2存储进入下一轮老鼠的索引顺序 如果当前有groups个组,那么会有groups个老鼠进入下一轮,则没有进入下一轮的排名都为groups+1如果只有一个组,那么最大的那个排名即为1. #include <iostream> #inc…