hdu1151 Air Raid

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HDU1151 Air Raid —— 最小路径覆盖

题目链接:https://vjudge.net/problem/HDU-1151 Air Raid Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5630 Accepted Submission(s): 3785 Problem Description Consider a town where all the streets a…

Hdu1151 Air Raid(最小覆盖路径)

Air Raid Problem Description Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an intersection and walking through town's streets you can never reach the same…

http://acm.hdu.edu.cn/showproblem.php?pid=1151 增广路的变种2:DAG图的最小路径覆盖=定点数-最大匹配数 #include<iostream> #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> using namespace std; ; int a[N][N]; int use[N]; int matc…

hdu1151 Air Raid，DAG图的最小路径覆盖

点击打开链接有向无环图的最小路径覆盖 = 顶点数- 最大匹配 #include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 150; int g[maxn][maxn]; int n, m; int link[maxn]; bool used[…

hdu1151 Air Raid 二分匹配

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1151 求最小路径覆盖二分图最小路径覆盖=点的个数-最大匹配. 代码: #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> using namespace std; #define maxn 125 int g[maxn][maxn]; int vis[maxn]; in…

hdu1151 Air Raid 基础匈牙利

#include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm> using namespace std; #define MAXN 150 int n; //十字路口的数量 int m; //路的个数 int map[MAXN][MAXN]; int x[MAXN], y[MAXN]; int mark[MAXN]; int search(int a) { ; i &l…

Air Raid[HDU1151]

Air RaidTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4974 Accepted Submission(s): 3347 Problem DescriptionConsider a town where all the streets are one-way and each street leads from one interse…