Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 53640   Accepted: 20448 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14721    Accepted Submission(s): 6968 Problem Description Every time it rains on Farmer John's fields, a pond forms over Bessie's…

Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13064    Accepted Submission(s): 6196 Problem Description Every time it rains on Farmer John's fields, a pond forms over Bessie's…

/* 网络流的最大流问题 刚学习Dinic算法.模版题 */ #include <cstring> #include <cstdio> #include <queue> using namespace std; ; const int inf = 0x3f3f3f3f; struct { int c,f; }edge[maxn][maxn]; int dis[maxn]; int v,e; bool bfs() { memset(dis,,sizeof dis); qu…

最大流首次体验感受—— 什么是最大流呢? 从一个出发点(源点),走到一个目标点(汇点),途中可以经过若干条路,每条路有一个权值,表示这条路可以通过的最大流量. 最大流就是从源点到汇点,可以通过的最大流量. 接下来我们看一个图—— 图1 这个图中,s是源点,t是汇点.期间可以经过2, 3, 4, 5, 6几个点.每条边上有两个权值,其中第一个表示当前通过这条边的流量,第二个表示这条边最大可以通过的流量. 最佳情况,即最大可以通过的流量的一种情况是这样的—— 图2 但还有一种情况,同样可以达到最大流…

pid=1532">Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8574    Accepted Submission(s): 3991 Problem Description Every time it rains on Farmer John's fields, a pond forms…

Drainage DitchesHal Burch Time Limit 1000 ms Memory Limit 65536 kb description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a…

                                                                                        Drainage Ditches   Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water f…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1532 思路: 网络流最大流的入门题,直接套模板即可~ 注意坑点是:有重边!!读数据的时候要用“+=”替换“=”. 对网络流不熟悉的,给一篇讲解:http://www.cnblogs.com/ZJUT-jiangnan/p/3632525.html. ✧(≖ ◡ ≖✿)我是看这篇博客才入门的. 代码: #include <cstdio> #include <cstring> #inclu…

点击打开链接 Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 49648   Accepted: 18829 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is cove…

http://poj.org/problem?id=1273 Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 62708   Accepted: 24150 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means…

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 63924   Accepted: 24673 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

Drainage Ditches Time Limit: 1000MS Memory Limit: 10000K Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time…

http://poj.org/problem? id=1273 Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 55235   Accepted: 21104 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This mean…

Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 16314    Accepted Submission(s): 7748 Problem Description Every time it rains on Farmer John's fields, a pond forms over Bessie'…

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 76000   Accepted: 29530 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

一.Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by water for awhile and takes quite a long time to regrow. Thus, Farmer John has built a set of drainag…

A - Drainage Ditches Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u   Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by wa…

Drainage Ditches Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8861    Accepted Submission(s): 4141 Problem Description Every time it rains on Farmer John's fields, a pond forms over Bessie's…

最大流问题.ISAP算法.注意可能会有重边,不过我用的数据结构支持重边.距离d我直接初始化为0,也可以用BFS逆向找一次. ----------------------------------------------------------------------- #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<vector>…

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 64044   Accepted: 24718 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

Drainage Ditches Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 5   Accepted Submission(s) : 3 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Every time it rains on…

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 59176   Accepted: 22723 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

Drainage Ditches Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 85250   Accepted: 33164 Description Every time it rains on Farmer John's fields, a pond forms over Bessie's favorite clover patch. This means that the clover is covered by…

最大流的第一道题,刚开始学这玩意儿,感觉好难啊!哎····· 希望慢慢地能够理解一点吧! #include<stdio.h> #include<string.h> #include<queue> using namespace std; #define inf 1000000 #define min(a,b) a<b?a:b int map[210][210],pre[210],maxf[210]; int n,m; int bfs()//搜索,截止找不到增广路…

题意: 给出一个有向图,以及边上的容量上限,求最大流.(有重边,要将容量上限叠加) 思路: 用最简单的EK+BFS解决.每次搜到一条到达终点的路径,就立刻退出,更新ans,然后再回头修改图中的当前flow状况(这就得靠记录路径了).当当前图没有到达终点的路径图,流已经饱和,可以结束程序了. #include <bits/stdc++.h> #define LL long long #define pii pair<int,int> #define INF 0x7f7f7f7f us…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1532 感觉题意不清楚,不知道是不是个人英语水平问题.本来还以为需要维护入度和出度来找源点和汇点呢,看讨论才知道1就是起点,m就是汇点..好想把代码写的工程化一点. #include <stdio.h> #include <string.h> #include <queue> #include <algorithm> using namespace std; c…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1532 题目大意是:农夫约翰要把多个小池塘的水通过池塘间连接的水渠排出去,从池塘1到池塘M最多可以排多少的水流量,给定水渠和连接的两个小池塘,以及该水渠的流量,求最大流. 其实就是裸的最大流,源点是1号池塘,汇点是M号池塘,从1到M做一个dinic算法求出最大流就行,但是我一直WA,怎么也改不对,后来发现是因为自己喜欢用vector建边建图的原因,对于输入多组样例时,没有初始化上组样例的vector数…

题意:输入m n, m是边数,n是点数. 接下来m行: 起点,终点,容量.求以 1 为源点, n为汇点的最大流. #include<stdio.h> #include<string.h> #include<queue> #include<algorithm> using namespace std; const int INF = 0xfffffff; + ; //邻接矩阵存放图. int flow[MAXN][MAXN]; //mark[]标记是否访问过,…

http://poj.org/problem?id=1273 用Dinic求最大流的模板题,注意会有重边. 邻接矩阵建图 #include<stdio.h> #include<string.h> #include<queue> #include<algorithm> using namespace std; ; const int INF = 0x3f3f3f3f; int flow[maxn][maxn];//残量 int m,n; int dis[max…