3940: [Usaco2015 Feb]Censoring Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 367  Solved: 173[Submit][Status][Discuss] Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty  of materia…

3940: [Usaco2015 Feb]Censoring Time Limit: 10 Sec  Memory Limit: 128 MB Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty  of material to read while waiting around in the barn during…

Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty  of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest  issue contains a rather in…

3942: [Usaco2015 Feb]Censoring Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the late…

题目链接:BZOJ - 3942 题目分析 我们发现,删掉一段 T 之后,被删除的部分前面的一段可能和后面的一段连接起来出现新的 T . 所以我们删掉一段 T 之后应该接着被删除的位置之前的继续向后匹配. 那么我们维护一个栈,一直向后匹配,如果栈顶出现了 T ,就弹出 T 个字符,然后继续从新的栈顶向后匹配就可以了. 匹配使用 KMP 算法. 代码 #include <iostream> #include <cstdio> #include <cstring> #inc…

Description 有两个字符串,每次用一个中取出下一位,放在一个字符串中,如果当前字符串的后缀是另一个字符串就删除. Sol KMP+栈. 用一个栈来维护新加的字符串就可以了.. 一开始我非常的naive,写了个链表,只能过5个点,因为起始位置不太好搞... Code /************************************************************** Problem: 3942 User: BeiYu Language: C++ Result:…

好久没写kmp都不会写了-- 开两个栈,s存当前串,c存匹配位置 用t串在栈s上匹配,栈每次入栈一个原串字符,用t串匹配一下,如果栈s末尾匹配了t则弹栈 #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=1000005; int n,m,c[N],top,ne[N]; char a[N],b[N],s[N]; void gtnxt() { ne[0…

AC自动机.为什么洛谷水题赛会出现这种题然而并不会那么题意就不说啦 .终于会写AC自动机判断是否是子串啦...用到kmp的就可以用AC自动机水过去啦 #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<queue> using namespace std; #define rep(i,s,t) for(int i=s;i<=t;…

[BZOJ3942][Usaco2015 Feb]Censoring Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the…

3942: [Usaco2015 Feb]Censoring Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 375  Solved: 206[Submit][Status][Discuss] Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material…

3942: [Usaco2015 Feb]Censoring Time Limit: 10 Sec Memory Limit: 128 MB Submit: 964 Solved: 480 [Submit][Status][Discuss] Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material…

点此看题面 大致题意: 给你一个文本串和\(N\)个模式串,要你将每一个模式串从文本串中删去.(此题是[BZOJ3942][Usaco2015 Feb]Censoring的升级版) \(AC\)自动机 这是一道\(AC\)自动机的简单运用题. 题解 我们可以用一个\(ans[\) \(]\)字符数组来存储最后的答案,并用一个\(lst[\) \(]\)数组来记录字符串中每一位上次被访问时所到达的\(Trie\)上的节点. 如果找到了一个长度为\(len\)的模式串要删去,我们可以将\(ans\)…

题目传送门 题目描述: FJ把杂志上所有的文章摘抄了下来并把它变成了一个长度不超过105的字符串S.他有一个包含n个单词的列表,列表里的n个单词记为t1…tN.他希望从S中删除这些单词.FJ每次在S中找到最早出现的列表中的单词(最早出现指该单词的开始位置最小),然后从S中删除这个单词.他重复这个操作直到S中没有列表里的单词为止.(注意删除一个单词后可能会导致S中出现另一个列表中的单词)FJ注意到列表中的单词不会出现一个单词是另一个单词子串的情况,这意味着每个列表中的单词在S中出现的开始位置是互不…

bzoj 3940 Censoring 题目描述 FJ把杂志上所有的文章摘抄了下来并把它变成了一个长度不超过10^5的字符串S. 他有一个包含n个单词的列表,列表里的n个单词记为T1......Tn.他希望从S中删除这些单词. FJ每次在S中找到最早出现的列表中的单词(最早出现指该单词的开始位置最小),然后从S中删除这个单词. 他重复这个操作直到S中没有列表里的单词为止. 注意删除一个单词后可能会导致S中出现另一个列表中的单词 FJ注意到列表中的单词不会出现一个单词是另一个单词子串的情况,这意味…

Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rather inap…

Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rather inap…

题目描述 Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rather inappropria…

Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rather inap…

维护一个栈...如果栈顶出现了要被删除的字符串就全删掉就好了,判断的话...kmp就行了 /************************************************************** Problem: 3942 User: rausen Language: C++ Result: Accepted Time:224 ms Memory:11548 kb *******************************************************…

[题目描述] FJ把杂志上所有的文章摘抄了下来并把它变成了一个长度不超过10^5的字符串S.他有一个包含n个单词的列表,列表里的n个单词 记为t_1...t_N.他希望从S中删除这些单词.  FJ每次在S中找到最早出现的列表中的单词(最早出现指该单词的开始位置最小),然后从S中删除这个单词.他重复这个操作直到S中 没有列表里的单词为止.注意删除一个单词后可能会导致S中出现另一个列表中的单词  FJ注意到列表中的单词不会出现一个单词是另一个单词子串的情况,这意味着每个列表中的单词在S中出现的开始位…

[题目大意] 有一个S串和一个T串,长度均小于1,000,000,设当前串为U串,然后从前往后枚举S串一个字符一个字符往U串里添加,若U串后缀为T,则去掉这个后缀继续流程. [样例输入] whatthemomooofun moo [样例输出] whatthefun     [题解] 我能说这是可持久化的kmp吗?(并没有此种术语) kmp的过程中,用一个栈来存当前U串,如果匹配到了,弹出即可,然后j指针有恢复到历史的状态,这个状态可以用f数组来存. #include<iostream> #in…

题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=3943 题意: 有n只队伍,每个队伍有一个编号a[i]. 每场比赛有两支队伍参加,然后选一支队伍淘汰.共进行n-1场比赛,然后比赛结束. 若某场比赛是队伍i和j参加,则该场比赛的得分为a[i] xor a[j]. 问最大的总得分. 题解: 每两支队伍(i,j)连一条边,边权为a[i] xor a[j]. 然后求最大生成树即可. AC Code: #include <iostream> #…

显然dp[i][j]=ps[i-1][j-1]-sigma(dp[k<i][l<j],a[i][j]=a[k][l]) 考虑对于每一种颜色都开一颗区间线段树,但是空间不够. 所以我们可以动态开节点的权值线段树即可. 因为ij写反了调了30min. 然后发现空间的问题我们可以分治啊,按照纵坐标分治,然后处理左半边对右半边的影响即可. 然后CDQ分治即可,空间是O(nm)的,时间复杂度是O(nmlogm)的. 复杂度怎么算?主定理套用即可. #include <cstdio> #inc…

题意:在文本串上删除一些字符串 每次优先删除从左边开始第一个满足的 删除后剩下的串连在一起重复删除步骤 直到不能删 题解:建fail 用栈存当前放进了那些字符 如果可以删 fail指针跳到前面去 好菜啊TAT 原来还有个优化 #include <bits/stdc++.h> using namespace std; ]; ]; int n, cnt, tot; ][]; ]; ]; ]; ]; ]; void insert() { int len = strlen(s); ; ; i <…

Code: // luogu-judger-enable-o2 #include<bits/stdc++.h> #define setIO(s) freopen(s".in","r",stdin) #define maxn 4100000 #define ll long long using namespace std; int u[maxn],v[maxn],p[3000],A[maxn]; ll arr[3000],val[maxn]; int n,…

3940: [Usaco2015 Feb]Censoring Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 723  Solved: 360[Submit][Status][Discuss] Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty  of materia…

[BZOJ3943][Usaco2015 Feb]SuperBull Description Bessie and her friends are playing hoofball in the annual Superbull championship, and Farmer John is in charge of making the tournament as exciting as possible. A total of N (1 <= N <= 2000) teams are p…

3943: [Usaco2015 Feb]SuperBull Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 300  Solved: 185 Description Bessie and her friends are playing hoofball in the annual Superbull championship, and Farmer John is  in charge of making the tournament as ex…

BZOJ_3940_[Usaco2015 Feb]Censoring_AC自动机 Description FJ把杂志上所有的文章摘抄了下来并把它变成了一个长度不超过10^5的字符串S.他有一个包含n个单词的列表,列表里的n个单词 记为t_1...t_N.他希望从S中删除这些单词.  FJ每次在S中找到最早出现的列表中的单词(最早出现指该单词的开始位置最小),然后从S中删除这个单词.他重复这个操作直到S中 没有列表里的单词为止.注意删除一个单词后可能会导致S中出现另一个列表中的单词  FJ注意到列…

BZOJ_3942_[Usaco2015 Feb]Censoring_KMP Description 有一个S串和一个T串,长度均小于1,000,000,设当前串为U串,然后从前往后枚举S串一个字符一个字符往U串里添加,若U串后缀为T,则去掉这个后缀继续流程. Input The first line will contain S. The second line will contain T. The length of T will be at most that of S, and all…