791. Custom Sort String - LeetCode】的更多相关文章

Question 791. Custom Sort String Solution 题目大意:给你字符的顺序,让你排序另一个字符串. 思路: 输入参数如下: S = "cba" T = "abcd" 先构造一个map,sMap key存储S中出现的字符,value存储字符在S中的位置 c -> 0 b -> 1 a -> 2 再构造一个int数组,sIdx sIdx,存储S中的字符在T字符串中出现的次数 遍历T字符串 如果字符在sMap中,sIdx…
题目链接:https://leetcode.com/problems/custom-sort-string/description/ S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 按顺序构造字符串 排序 日期 题目地址:https://leetcode.com/problems/custom-sort-string/description/ 题目描述 S and T are strings composed of lowercase letters. In S, no letter occurs more than once.…
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…
[抄题]: S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if…
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…
S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…
Sorting in Javascript with sort uses lexical sorting by default, which means it will sort in alphabetical order. That's fine for strings of characters, but it means that arrays of numbers don't sort in numerical order! To fix that, we'll pass a custo…