POJ 1041问题描述】的更多相关文章

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题目链接:http://poj.org/problem?id=1041 思路:懒得写了,直接copy吧:对于一个图可以从一个顶点沿着边走下去,每个边只走一次,所有的边都经过后回到原点的路.一个无向图存在欧拉回路的充要条件是每个顶点的度是偶数, 对于有向图存在欧拉回路的条件是每个顶点的出度等于入度(就是出去的边数等于进来的边数).根据这个首先判断存在欧拉回路不, 如果存在然后用DFS去找欧拉回路.DFS的思想等效于先找一个环,然后对环上所有点递归DFS,并且把这些递归产生的路插入这个环中. 实际上…
[题目链接] http://poj.org/problem?id=1041 [算法] 欧拉回路[代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #includ…
题目:http://poj.org/problem?id=1041 明明是欧拉回路字典序输出的模板. 优先队列存边有毒.写跪.学习学习TJ发现只要按边权从大到小排序连边就能正常用邻接表了! 还有一种存边的方法是把边的标号放到数组第二维里,达到一个桶的效果. 我当然知道那种模板是先dfs再在return的时候把边加进栈里最后倒序输出,可是这题为什么不正序呢? 然后WA了.发现可能先把一个点的度走完但此时其他点还有度这样的. 于是有了flag和return.然后就超时了. 再看看TJ,突然就明白了为…
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题目链接 求给出的图是否存在欧拉回路并输出路径, 从1这个点开始, 输出时按边的升序输出. 将每个点的边排序一下就可以. #include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <map> #include <set> #in…