23. Merge k Sorted Lists】的更多相关文章

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments…
21.Merge Two Sorted Lists 初始化一个指针作为开头,然后返回这个指针的next class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode* dummy = ); ListNode* p = dummy; while(l1 && l2){ if(l1->val <= l2->val){ p->next = l1; p = p-&…
一.题目说明 这个题目是23. Merge k Sorted Lists,归并k个有序列表生成一个列表.难度为Hard,实际上并不难,我一次提交就对了. 二.我的解答 就是k路归并,思路很简单,实现也不难. #include<iostream> #include<vector> using namespace std; struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {}…
Question 23. Merge k Sorted Lists Solution 题目大意:合并链表数组(每个链表中的元素是有序的),要求合并后的链表也是有序的 思路:遍历链表数组,每次取最小节点 Java实现: public ListNode mergeKLists(ListNode[] lists) { ListNode preHead = new ListNode(0); ListNode minNode = getMinNode(lists); ListNode tmpNode =…
题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 翻译 合并k个有序的链表 Hints Related Topics: LinkedList, Divide and Conquer, Heap Solution1:Divide and Conquer 参考 归并排序-维基百科 思路:分治,先分成两个子任务,然后递归子任务,最后回溯回来..这里就…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 这道题让我们合并k个有序链表,最终合并出来的结果也必须是有序的,之前做过一道 M…
1 题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 2 思路 当时看到这个题目就想到的是归并排序.好吧,但是,具体代码写不出来.题目给的是数组:public ListNode mergeKLists(ListNode[] lists),我就想,怎么归并排序,然后返回一个已经排好的,再进行递归.想破脑袋没想出来. 原来,可以赋值给一个Array…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ======= 合并k个链表形成一个已排序链表 思路: 如何合并两个有序链表?经典merge算法: ListNode *mergeList(ListNode *head1,ListNode *head2){ ListNode dummy(-); ListNode *h = &dummy; while(…
题目描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路: 分治方法.将K个List不断地分解为前半部分和后半部分.分别进行两个List的合并.最后将合并的结果合并起来. 代码如下: /** * Definition for singly-linked list. * public class ListNode { * int val;…
一天一道LeetCode系列 (一)题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. (二)解题 合并K个已拍好序的链表.剑指上有合并两个已排好序的链表的算法,那么K个数,我们可以采用归并排序的思想,不过合并函数可能需要修改一下,换成合并两个已排好序的链表的方法.代码如下: /** * Definition for singly-linked…