POJ 1298

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poj 1298 The Hardest Problem Ever

题目链接:http://poj.org/problem?id=1298 题目大意:按照所给的顺序要求将输入的字符串进行排列. #include <iostream> #include <cstdio> #include <cstring> using namespace std; int main () { ]= {"VWXYZABCDEFGHIJKLMNOPQRSTU"}; ]; ) { gets(ch); )//strcmp是字符的一个函数,也就…

#include<iostream>// chengdacaizi 注释!2008 11 05 #include<string> using namespace std; int main() { while(true) { string start;//用于控制循环 cin>>start;// if(start=="ENDOFINPUT")break; string text;//密码字符串; cin.ignore(,'\n');//关键步骤忽略…

poj 1298(水题）

The Hardest Problem Ever Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 24241 Accepted: 13227 Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was keeping himself alive. In orde…

POJ 1298 The Hardest Problem Ever【字符串】

Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was keeping himself alive. In order for him to survive, he decided to create one of the first ciphers. This cipher was so incredibly sound, that no one coul…

UVALive 4639 && SPOJ SPOINTS && POJ 3805 && AOJ 1298 Separate Points 求两个凸包是否相交难度:3

https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2640 http://www.spoj.com/problems/SPOINTS/en/ http://poj.org/problem?id=3805 http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1298 要…

POJ水题 1298

#include "stdafx.h" #include <iostream> #include <string> using namespace std; int main() { string tol,result; while(getline(cin,tol)) { unsigned i=; if(tol=="START") continue; else if(tol=="END") cout<<resu…

POJ 题目分类（转载）

Log 2016-3-21 网上找的POJ分类,来源已经不清楚了.百度能百度到一大把.贴一份在博客上,鞭策自己刷题,不能偷懒!! 初期: 一.基本算法: (1)枚举. (poj1753,poj2965) (2)贪心(poj1328,poj2109,poj2586) (3)递归和分治法. (4)递推. (5)构造法.(poj3295) (6)模拟法.(poj1068,poj2632,poj1573,poj2993,poj2996) 二.图算法: (1)图的深度优先遍历和广度优先遍历. (2)最短路…