print(x, end=' ') instead of print(x) to escape the default line-changing-output. print(str.ljust(size)) left-alignment with given size, samely, str.rjust(size) works just fine # Can you talk about the differences between the following commands? prin…
语法错误 语法错误又被称解析错误 >>> for i in range(1..10):print(i) File "<stdin>", line 1 for i in range(1..10):print(i) ^ SyntaxError: invalid syntax 语法分析器指出错误行,并且在检测到错误的位置前面显示一个小“箭头”. 错误是由箭头 前面 的标记引起的(或者至少是这么检测的) 异常 即使一条语句或表达式在语法上是正确的,当试图执行它时也…
continue: def func(): for i in range(1,11): if i % 2 == 0: continue # 作用是当符合上面的if判语句后,就直接跳过之后的语句,也就是不执行print(i) print (i) func() # 输出的结果是:1,3,5,7,9 break def func1(): for i in range(1,11): if i % 2 == 0: break # 作用是不满足if语句后,直接执行print(i) print (i) fun…
示例1: #循环退出,break continue.break 跳出最外层循环:continue跳出内层循环 #当 i=5时,通过continue 跳出当前if循环,不在执行if循环中后边的语句.i=6...i=9 继续执行,else语句也执行 #当i=8时,跳出for循环,不在执行后边的语句,for循环不正常结束,else语句也不执行 for i in xrange(10): import time time.sleep(1) if i ==5: continue if i ==8: brea…