Binary Number Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1287    Accepted Submission(s): 807 Problem Description For 2 non-negative integers x and y, f(x, y) is defined as the number of di…

Binary Number Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1879    Accepted Submission(s): 1133 Problem Description For 2 non-negative integers x and y, f(x, y) is defined as the number of di…

Binary Number Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1475    Accepted Submission(s): 933 Problem Description For 2 non-negative integers x and y, f(x, y) is defined as the number of dif…

Problem Description For non-negative integers x and y, f(x, y) , )=,f(, )=, f(, )=. Now given sets of non-negative integers A and B, for each integer b in B, you should find an integer a in A such that f(a, b) is minimized. If there are more than one…

专门为杭州电50周年礼事 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7236    Accepted Submission(s): 3936 Problem Description 也许你以前牢骚满腹 也许你依旧心怀忧伤 也许你近在咫尺 也许你我天各一方 对于每个学子 母校 永远航行在 生命的海洋 今年是我们杭电建校五十周年,这是…

B. Fi Binary Number     A Fi-binary number is a number that contains only 0 and 1. It does not contain any leading 0. And also it does not contain 2 consecutive 1. The first few such number are 1, 10, 100, 101, 1000, 1001, 1010, 10000, 10001, 10010,…

problem 693. Binary Number with Alternating Bits solution1: class Solution { public: bool hasAlternatingBits(int n) { ; ) { /* errr... if(n&1 && bit==1) return false; else if(n&1) bit = 1; if(n&1==0 && bit==0) return false; els…

链接:https://ac.nowcoder.com/acm/contest/897/J 来源:牛客网 Binary Number 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 32768K,其他语言65536K 64bit IO Format: %lld 题目描述 As a programmer, you are probably familiar with the binary representation of integers. That is, write an in…

Question 693. Binary Number with Alternating Bits Solution 思路:输入一个整数,它的二进制01交替出现,遍历其二进制字符串,下一个与上一个不等,返回true,如果有相等的就返回false Java实现: public boolean hasAlternatingBits(int n) { char last = '2'; // 非0非1即可 for (char c : Integer.toBinaryString(n).toCharArr…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input: 7 Output: False Ex…

Given head which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary representation of a number. Return the decimal value of the number in the linked list. Example…

题目如下: Given head which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary representation of a number. Return the decimal value of the number in the linked list. Ex…

#include<bits/stdc++.h> using namespace std; int n; int getBits1(int n)//求取一个数的二进制形式中1的个数. { int res=0; while(n) { if(n&1) res++; n>>=1; } return res; } int getBits2(int n) { int res=0; while(n) { res++; n=n&(n-1);//一次消去1个1哦 } return r…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3711 题意:两个数集合,找二进制下位数不同最少的数,如果一样,找集合数最小的. 暴力枚举 #include <bits/stdc++.h> using namespace std; ; int n, m; int a[maxn], b[maxn]; int ok(int x, int y) { int xx = x, yy = y; ; if(x > y) swap(x, y); while…

http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6439    Accepted Submission(s): 3886 Problem Description A friend of you is doing res…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12157    Accepted Submission(s): 5036 Problem Description There is a pile of n wooden sticks. The length and weight of each stick a…

http://acm.hdu.edu.cn/showproblem.php? pid=1052 Tian Ji -- The Horse Racing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 18058    Accepted Submission(s): 5239 Problem Description Here is a f…

Problem Description The three hands of the clock are rotating every second and meeting each other many times everyday. Finally, they get bored of this and each of them would like to stay away from the other two. A hand is happy if it is at least D de…

我要参加全国软件设计大赛C/C++学生语言组,前一个假设<C训练和演习,并总结手>没看完,请阅读上述并根据所作的训练,然后做下面的练习. 门户:http://blog.csdn.net/liuqiyao_01/article/details/8477666 杭电acm阶段之理工大版 [671原创.欢迎转载] 下面题均为杭电acm网页的题号 首页http://acm.hdu.edu.cn/ 题库入口vol=1">http://acm.hdu.edu.cn/listproblem.…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101  Example 2: Input: 7 Output: False E…

Description Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input: 7 Output: False Ex…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input: 7 Output: False Ex…

Fibbonacci Number Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25027    Accepted Submission(s): 11501 Problem Description Your objective for this question is to develop a program which will g…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历判断 判断是否是交替模式 位运算 日期 题目地址:https://leetcode.com/problems/binary-number-with-alternating-bits/description/ 题目描述 Given a positive integer, check whether it has alternating bits:…

题目要求第k个没有连续两个1的二进制数. 这算数位DP吧,只不过以前遇到的是统计区间的数字情况,而这题是求第几个数字,差不多是反过来的. 本来我想用状态dp[i][0/1]表示长度i末尾0或1的二进制数个数,发现这样好像没法解. 最后需要根据数位DP状态的值推算出要求二进制数各个位置是0还是1,这个肯定是从高位到低位确定——所以应该反过来表示状态: dp[i][0/1]:长度i开头为0或1的二进制数个数 最后的求解: 先利用dp[i][1]的值确定出要求二进制的位数 位数知道后,最高位得是1 最…

这个话题.简单的数学. 对于函数,f(x)=5*x^13+13*x^5+k*a*x,输入k,对于休闲x,一个数字的存在a,使f(x)是65可分. 对于休闲x. 因此,当x = 1时间,f(x) = 18 + a* k.满足被65整除. 也就是(18 + a * k)% 65 = 0. 所以,一切都非常easy了. 以下的是AC的代码: #include <iostream> using namespace std; int main() { int k; while(cin >>…

也可以看看GCD Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11122    Accepted Submission(s): 4696 Problem Description 有三个正整数a,b,c(0<a,b,c<10^6),当中c不等于b.若a和c的最大公约数为b,现已知a和b,求满足条件的最小的c.   Input 第一行…

A == B ? Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 64239    Accepted Submission(s): 10060 Problem Description Give you two numbers A and B, if A is equal to B, you should print "YES"…

这个夏天不AC Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 28304    Accepted Submission(s): 15023 Problem Description "今年暑假不AC?" "是的." "那你干什么呢?" "看世界杯呀.笨蛋." &quo…