链接: https://codeforces.com/contest/1265/problem/A 题意: A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa&…

题目链接:https://codeforces.com/contest/1265/problem/A 题意 给出一个由 a, b, c, ? 组成的字符串,将 ? 替换为 a, b, c 中的一个字母,问能否字符串中所有相邻字母都不同. 题解 除非一开始字符串就不合法,否则一定可以构造出合法的字符串,因为共有三个字母可选,而替换时最多需要判断前后两个位置. 代码 #include <bits/stdc++.h> using namespace std; void solve() { strin…

链接: https://codeforces.com/contest/1265/problem/D 题意: An integer sequence is called beautiful if the difference between any two consecutive numbers is equal to 1. More formally, a sequence s1,s2,-,sn is beautiful if |si−si+1|=1 for all 1≤i≤n−1. Trans…

链接: https://codeforces.com/contest/1265/problem/E 题意: Creatnx has n mirrors, numbered from 1 to n. Every day, Creatnx asks exactly one mirror "Am I beautiful?". The i-th mirror will tell Creatnx that he is beautiful with probability pi100 for al…

链接: https://codeforces.com/contest/1265/problem/C 题意: So the Beautiful Regional Contest (BeRC) has come to an end! n students took part in the contest. The final standings are already known: the participant in the i-th place solved pi problems. Since…

链接: https://codeforces.com/contest/1265/problem/B 题意: You are given a permutation p=[p1,p2,-,pn] of integers from 1 to n. Let's call the number m (1≤m≤n) beautiful, if there exists two indices l,r (1≤l≤r≤n), such that the numbers [pl,pl+1,-,pr] is a…

题目链接:https://codeforces.com/contest/1265/problem/E 题目大意: 有 \(n\) 个步骤,第 \(i\) 个步骤成功的概率是 \(P_i\) ,每一步只有成功了才会进入下一步,失败了会从第 \(1\) 步重新开始测.请问成功的期望步数是多少? 解题思路: 设期望步数是 \(S\) ,则有公式如下: 实现代码如下: #include <bits/stdc++.h> using namespace std; typedef long long ll;…

题目链接:https://codeforces.com/contest/1265/problem/B 题意 给出大小为 $n$ 的一个排列,问对于每个 $i(1 \le i \le n)$,原排列中是否有一个大小为 $i$ 的连续子排列. 题解 从小到大构造排列,记录当前排列中数的最小下标和最大下标,若最小下标和最大下标的间距刚好为排列的长度,则说明大小为 $i$ 的排列是连续的. 代码一 #include <bits/stdc++.h> using namespace std; void s…

题目链接:https://codeforces.com/contest/1265/problem/C 题意 从大到小给出 $n$ 只队伍的过题数,要颁发 $g$ 枚金牌,$s$ 枚银牌,$b$ 枚铜牌,要求: $g < s, g < b$ $g + s + d \le \lfloor \frac{n}{2} \rfloor$ 金牌队伍的过题数大于银牌,银牌队伍的过题数大于铜牌 输出颁发奖牌数最多的一种方案. 题解 根据第三个要求,奖牌一定是按过题数的大小颁发的. 金牌只颁发给过题最多数的队伍,…

题意 给出排成一列的 \(n\) 个格子,你要从 \(1\) 号格子走到 \(n\) 号格子之后(相当于 \(n+1\) 号格子),一旦你走到 \(i+1\) 号格子,游戏结束. 当你在 \(i\) 号格子时,你有 \(p_i\) 的概率走到 \(i+1\) 号格子,否则你会返回最近的一个 checkpoint (存档点),最近的存档点是指 \(max\{x|x\leq i \; and \; ischeckpoint(x)\}\) .对于每个 \(query x\) ,会把 \(x\) 号格子…

题目传送门 /* 题意:找到一个字符串p,使得它和s,t的不同的总个数相同 贪心:假设p与s相同,奇偶变换赋值,当是偶数,则有答案 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <iostream> using namespace std; ; const int INF = 0x3f3f3f3f; int p[MAXN…

链接:http://codeforces.com/contest/1265 A. Beautiful String A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "a…

A. Beautiful String (暴力) 题目链接 题目大意: 给定一个字符串,只有 \(?a\ b\ c\ ?\) ,问是否存在一种将所有的 \(?\) 替换成 \(a\ b\ c\) ,使得任意相邻的字符不同的方法. 大致思路: 其实可以发现问号都可以通过枚举使得其合法,若出现不合法必然除去问好已经不合法,暴力枚举即可. 代码: 点击展开代码 #include<bits/stdc++.h> using namespace std; const int N=1e5+10; char…

链接: https://codeforces.com/contest/1182/problem/C 题意: You are given n words, each of which consists of lowercase alphabet letters. Each word contains at least one vowel. You are going to choose some of the given words and make as many beautiful lyric…

C. Beautiful Numbers 题目连接: http://www.codeforces.com/contest/300/problem/C Description Vitaly is a very weird man. He's got two favorite digits a and b. Vitaly calls a positive integer good, if the decimal representation of this integer only contains…

题目连接:http://codeforces.com/contest/676/problem/C 题意:一串字符串,最多改变k次,求最大的相同子串 题解:很明显直接尺取法 #include<cstdio> #include<cstring> #include<cmath> #include<string> #include<set> #include<map> #include<vector> #include<qu…

B. Equidistant String Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/545/problem/B Description Little Susie loves strings. Today she calculates distances between them. As Susie is a small girl after all, her strings conta…

B. Beautiful Paintings 题目连接: http://www.codeforces.com/contest/651/problem/B Description There are n pictures delivered for the new exhibition. The i-th painting has beauty ai. We know that a visitor becomes happy every time he passes from a painting…

[Link]:http://codeforces.com/contest/828/problem/C [Description] 让你猜一个字符串原来是什么; 你知道这个字符串的n个子串; 且知道第i个字符t[i],在k[i]个位置出现过; 且告诉你这k[i]个位置在哪里; 数据不会产生矛盾; 让你输出最终的字符串,输出字典序最小的那个; [Solution] 对于输入的n个子串; 对于每个位置; 看看那个位置有没有子串之前出现过,没有的话,就放在那个位置; 否则,如果当前这个子串ti的长度比原…

Beautiful Sequence Beautiful Mirrors Beautiful Bracket Sequence (easy version) Beautiful Sequence \[ Time Limit: 1000 ms\quad Memory Limit: 256 MB \] 首先我们可以考虑到 \(0\) 只能 和 \(1\) 放在一起.\(3\) 只能和 \(2\) 放在一起,那么我们想办法先把 \(0\) 和 \(3\) 凑出来,最后就剩下 \(1\) 和 \(2\)…

题目链接:https://codeforces.com/contest/1385/problem/D 题意 一个小写字母串称为 $c-good\ string$,如果至少满足以下条件之一: 字符串长度为 $1$,包含字母 $c$ 字符串前一半都为字母 $c$,后一半为 $(c+1)-good\ string$ 字符串后一半都为字母 $c$,前一半为 $(c+1)-good\ string$ 计算将一个长为 $n = 2^k$ 的小写字母串变为 $a-good\ string$ 至少需要替换多少个…

Median String time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given two strings ss and tt, both consisting of exactly kk lowercase Latin letters, ss is lexicographically less than …

题目链接:http://www.codeforces.com/problemset/problem/271/A题意:给你一个四位数,求比这个数大的最小的满足四个位的数字不同的四位数.C++代码: #include <iostream> #include <algorithm> using namespace std; bool chk(int x) { ]; ; i < ; i ++) { a[i] = x % ; x /= ; } sort(a, a + ); ; i &l…

A. Beautiful Year time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after t…

B. Beautiful Paintings time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output There are n pictures delivered for the new exhibition. The i-th painting has beauty ai. We know that a visitor becomes…

把字符串看作是26进制的数,从后往前翻译,那么就可以把两个串变成对应的26进制的数字,那么只要把两个数加起来除以二就得到中间的串对应的数了,同理再转化回来就行了.但是这样会有一个问题就是串的长度有2e5,26的2e5次方显然不可求,所以需要对每一位进行手动的加和运算.对于两个串,我们假设a串从后往前的每一位对应的数值为a0, a1, a2...,b串从后往前的每一位对应的数值为b0, b1, b2...对于进制加法,有 扔一下垃圾代码: #include <iostream> #include…

B. Obsessive String   Hamed has recently found a string t and suddenly became quite fond of it. He spent several days trying to find all occurrences of t in other strings he had. Finally he became tired and started thinking about the following proble…

// https://codeforces.com/contest/1265/problem/D /* 感觉像是遍历的思维构造题 有思路就很好做的 可以把该题想象成过山车或者山峰...... */ #include<iostream> #include<cstdio> using namespace std; int n; int cnt[5], last[5]; // last 是记录当前还有多少 0, 1, 2, 3 int ans[100005]; bool ok; int…

D. Binary String Minimizing You are given a binary string of length n (i. e. a string consisting of n characters '0' and '1'). In one move you can swap two adjacent characters of the string. What is the lexicographically minimum possible string you c…

A题 链接 思路分析: 因为只需要做到相邻的不相同,利用三个不同的字母是肯定可以实现的, 所以直接先将所有的问号进行替换,比如比前一个大1,如果与后面的冲突,则再加一 代码(写的很烂): #include <bits/stdc++.h> using namespace std; int check( string a) { for (int i = 0; i < a.length(); ++i) { if (i==0) { if (a[i]==a[i+1]) { return 0; }…