Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

题目要求 Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目分析及思路 题目给出一个N叉树,要求得到它的最大深度.该最大深度为根结点到最远叶结点的结点数.可以使用递归,遍历孩子结点. python代码​ """…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. /* // Definiti…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

原题链接 思路: 简单bfs class Solution { public: int maxDepth(Node *root) { int depth = 0; if (root == NULL) return 0; queue<Node *> q; q.push(root); while (q.size() > 0) { depth++; int len = q.size(); for (int i = 0; i < len; i++) { vector<Node *&g…

Question 559. Maximum Depth of N-ary Tree Solution 题目大意:N叉树求最大深度 思路:用递归做,树的深度 = 1 + 子树最大深度 Java实现: /* // Definition for a Node. class Node { public int val; public List<Node> children; public Node() {} public Node(int _val,List<Node> _children…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS BFS 日期 题目地址:https://leetcode.com/problems/maximum-depth-of-n-ary-tree/description/ 题目描述 Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes…

Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. For example, given a 3-ary tree: We should return its max depth, which is 3. Note: The dept…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目标签:Tree 这道题目给了我们一个二叉树,要我们找到最大深度,就是从root点到最深的那个点之间点的数量.利用post order 来遍历二叉树,对于每一个点,它的两个chi…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

Problem: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 初看本题第一印象为递归写法.首先找出终止条件:node == NULL.若未进入递归终止状态,则分左子树和又子树进行递归,最终返回累加最大的值.其代码如下: /*…

Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. BFS碰到一个叶子结点就可以了. class Solution { public: int minDepth(TreeNo…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求树的高度. 深度优先搜索遍历.递归实现. /** * Definition for a binary tree node. * public class TreeNode { *…

题目描述: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 解题思路: 分左子树和右子数递归调用. 代码如下: /** * Definition for a binary tree node. * public class Tr…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 分析:求二叉树的最大深度 解法一:很容易想到的便是递归(深度优先搜索) (1)如果根节点是空,则返回0:否则转到(2) (2)  l = 左子树的最大深度; r = 右子树的最大深…

题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求二叉树的深度,递归一下就可以求到了. python新手(我)发现python中没有三元运算符,不过可以用true_part if condition else false…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路:直接利用递归,此处二叉树的C++语言定义值得参考.…

Maximum Depth of Binary Tree Total Accepted: 63668 Total Submissions: 141121 My Submissions Question Solution Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the…

104. Maximum Depth of Binary Tree -- Easy 方法 使用递归 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [,,,,], / \ / \ 方法一:采用…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

题目要求 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. 题目分析及思路 给定一棵二叉树,要求返回它的最大深度.最大深度是指在从根结点到最远叶结点…

描述 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,1…

可能是因为我是按难度顺序刷的原因,这个其实在之前的几道题里面已经写过了.题目如下: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 然后就直接拿之前的代码了: /** * Definition for binary tree *…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题解: 题意比较清楚, 找到从root出发最长的一条路径的长度. 采用DFS即可. 相似的一道题: Minimux Depth of Binary Tree 解法: http://…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 解题思路: 递归,JAVA实现如下: public int maxDepth(TreeNode root) { if(root==null) return 0; return Ma…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left;…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路:非常基础的一个题.DFS就可以.代码例如以下: /** * Definition for a binary tree node. * public class TreeNod…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路: 递归求解二叉树的深度,左右子树较深的+1(.解释主要原因:存在根节点) 实现代码: /** * Definition for a binary tree node. * s…