No.121 MaxProfit 买卖股票的最佳时机 题目 给定一个数组,它的第 i 个元素是一支给定股票第 i 天的价格. 如果你最多只允许完成一笔交易(即买入和卖出一支股票),设计一个算法来计算你所能获取的最大利润. 注意你不能在买入股票前卖出股票. 示例 输入: [7,1,5,3,6,4] 输出: 5 解释: 在第 2 天(股票价格 = 1)的时候买入,在第 5 天(股票价格 = 6)的时候卖出,最大利润 = 6-1 = 5 . 注意利润不能是 7-1 = 6, 因为卖出价格需要大于买入价…

Markdown版本笔记 我的GitHub首页 我的博客 我的微信 我的邮箱 MyAndroidBlogs baiqiantao baiqiantao bqt20094 baiqiantao@sina.com 领扣-121/122 最佳买卖时机 Best Time to Buy and Sell MD 目录 目录买卖股票的最佳时机 -121题目暴力法贪心算法(波峰波谷法)优化买卖股票的最佳时机 II -122题目波峰波谷法波峰波谷法优化累加法买卖股票的最佳时机 III -123动态规划 二维数组…

121题目描述: 解题:记录浏览过的天中最低的价格,并不断更新可能的最大收益,只允许买卖一次的动态规划思想. class Solution { public: int maxProfit(vector<int>& prices) { if(prices.size() == 0) return 0; int min_prices = prices[0]; int max_profit = 0; for(int i = 1 ; i < prices.size(); i++ ){ if…

121. Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.…

题目1----121. 买卖股票的最佳时机I: 链接:https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock/ 给定一个数组,它的第 i 个元素是一支给定股票第 i 天的价格. 如果你最多只允许完成一笔交易(即买入和卖出一支股票),设计一个算法来计算你所能获取的最大利润. 解答: 限制只能买入卖出一次 DP1: buy[i]记录截止到第i天是买入的状态的最小花费(值为负数) class Solution { public:…

这类问题有一个通法 https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock-iii/solution/yi-ge-tong-yong-fang-fa-tuan-mie-6-dao-gu-piao-wen/ 再说吧,该睡觉了 122 只要是增加的买就完事了 class Solution { public: int maxProfit(vector<int>& prices) { int max = 0 ; if(p…

Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 分析:…

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作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 C++ 解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/best-time-to-buy-and-sell-stock/ Total Accepted: 98941 Total Submissions: 274449 Difficulty: Easy 题目描述 S…

Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. [思路]…