The Meeting Place Cannot Be Changed Problem Description The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost building in north direction. At some points on the…
题目链接 The Meeting Place Cannot Be Changed 二分答案即可. check的时候先算出每个点可到达的范围的区间,然后求并集.判断一下是否满足l <= r就好了. eps我设了1e-7. #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for(int i(a); i <= (b); ++i) + ; ; double mi, ma; struct node{ dou…
                                                               B. The Meeting Place Cannot Be Changed The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmost build…
time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output The main road in Bytecity is a straight line from south to north. Conveniently, there are coordinates measured in meters from the southernmo…
题意:题意:给出n个人的在x轴的位置和最大速度,求n个人相遇的最短时间. 析:二分时间,然后求并集,注意精度,不然会超时. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream>…
题意:在一维坐标轴上,给定n个点的坐标以及他们的最大移动速度,问他们能聚到某一点处的最短时间. 分析: 1.二分枚举最短时间即可. 2.通过检查当前时间下,各点的最大移动范围之间是否有交集,不断缩小搜索范围. 3.相当于二分枚举找右临界线,符合要求的点都在右边. 4.通过给二分一个查找次数的上界,eg:k=200,而不是dcmp(l, r)<=0,后者会tle. 5.检查是否有交集,就是以第一个点的最大移动区间为标准,不断与其他区间取交集并更新再继续比较. #include<cstdio>…
Link 题意:给出$n$个坐标$x_i$,$n$个速度$v_i$问使他们相遇的最短时间是多少. 思路:首先可肯定最终相遇位置必定在区间$[0,max(x_i)]$中,二分最终位置,判断左右部分各自所花时间,缩小范围即可. /** @Date : 2017-05-09 22:07:43 * @FileName: 782B.cpp * @Platform: Windows * @Author : Lweleth (SoundEarlf@gmail.com) * @Link : https://gi…
链接:http://codeforces.com/problemset/problem/782/B 题意: N个点,需要找到一个点使得每个点到这个点耗时最小,每个点都同时开始,且都拥有自己的速度 题解: 对于一个确定的位置,如果耗时最久的点在右边,则这个位置可以往右靠,否则就往左靠,这样,一个二分的解法就形成了 import java.lang.Math; import java.util.Scanner; public class CodeForces_403_B { private stat…
地址:http://codeforces.com/contest/782/problem/B 题目: B. The Meeting Place Cannot Be Changed time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output The main road in Bytecity is a straight line from…
780B - The Meeting Place Cannot Be Changed 思路: 二分答案: 代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define eps 1e-7 #define INF 1e18 #define maxn 60005 int n; double xi[maxn]…