N couples sit in 2N seats arranged in a row and want to hold hands. We want to know the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats. The people…

Leetcode之并查集专题-765. 情侣牵手(Couples Holding Hands) N 对情侣坐在连续排列的 2N 个座位上,想要牵到对方的手. 计算最少交换座位的次数,以便每对情侣可以并肩坐在一起. 一次交换可选择任意两人,让他们站起来交换座位. 人和座位用 0 到 2N-1 的整数表示,情侣们按顺序编号,第一对是 (0, 1),第二对是 (2, 3),以此类推,最后一对是 (2N-2, 2N-1). 这些情侣的初始座位  row[i] 是由最初始坐在第 i 个座位上的人决定的.…

N couples sit in 2N seats arranged in a row and want to hold hands. We want to know the minimum number of swaps so that every couple is sitting side by side. A swapconsists of choosing any two people, then they stand up and switch seats. The people a…

N couples sit in 2N seats arranged in a row and want to hold hands. We want to know the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats. The people…

N couples sit in 2N seats arranged in a row and want to hold hands. We want to know the minimum number of swaps so that every couple is sitting side by side. A swap consists of choosing any two people, then they stand up and switch seats. The people…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/couples-holding-hands/description/ 题目描述: N couples sit in 2N seats arranged in a row and want to hold hands. We want to know the minimum number of swaps so th…

▶ n 对夫妻共 2n 个人随机坐成一排,“交换其中某两人的位置” 称为一次操作,求最少的操作此次数,使 n 对夫妻两人都相邻.初始座位为非负整数列 D1n-1,其中值为 2k 和 2k+1 的两个元素为一对夫妻.(本体尚未有 Discuss或 Solution) ● 代码,2 ms,顺着梳理 class Solution { public: int minSwapsCouples(vector<int>& row) { int i, len; ; i < row.size();…

Given an unsorted integer array, find the first missing positive integer. For example,Given [1,2,0] return 3,and [3,4,-1,1] return 2. Your algorithm should run in O(n) time and uses constant space. 这道题让我们找缺失的首个正数,由于限定了O(n)的时间,所以一般的排序方法都不能用,最开始我没有看到还限…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…