题目链接  2016 青岛网络赛  Problem C 题意  给出一些敏感词,和一篇文章.现在要屏蔽这篇文章中所有出现过的敏感词,屏蔽掉的用$'*'$表示. 建立$AC$自动机,查询的时候沿着$fail$指针往下走,当匹配成功的时候更新$f[i]$ $f[i]$表示要屏蔽以第$i$个字母结尾的长度为$f[i]$的字符串. #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i &l…

题目链接  2016 Qingdao Online Problem I 题意  在一棵给定的树上删掉一条边,求剩下两棵树的树的直径中较长那的那个长度的期望,答案乘上$n-1$后输出. 先把原来那棵树的直径求出来.显然删掉的边不是这条直径上的边,那么这时答案就是这条直径的长度. 否则就是直径的某个端点到某一个点(要求连通)的距离的最大值. 在整条链上做两次$DP$之后枚举取较大值即可. #include <bits/stdc++.h> using namespace std; #define r…

题意:将匹配的串用'*'代替 tips: 1 注意内存的使用,据说g++中指针占8字节,c++4字节,所以用g++交会MLE 2 注意这种例子, 12abcdbcabc 故失败指针要一直往下走,否则会丢弃一些串 3 当出现非英文字符时应先将指针指向根节点,否则出现 11cyc,,,,,,,y 时结果为c,,,,,,**(由不止一种Bug造成的),正确的应为c,,,,,,,y,然而很多题解这样也过了~ #include<cstdio> #include<iostream> #incl…

Flyer Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 386    Accepted Submission(s): 127 Problem Description The new semester begins! Different kinds of student societies are all trying to adver…

Mex Time Limit: 15000/5000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 623    Accepted Submission(s): 209 Problem Description Mex is a function on a set of integers, which is universally used for impartial game t…

I Count Two Three 31.1% 1000ms 32768K   I will show you the most popular board game in the Shanghai Ingress Resistance Team. It all started several months ago. We found out the home address of the enlightened agent Icount2three and decided to draw hi…

Herbs Gathering 10.76% 1000ms 32768K   Collecting one's own plants for use as herbal medicines is perhaps one of the most self-empowering things a person can do, as it implies that they have taken the time and effort to learn about the uses and virtu…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6215 题意:给你长度为n的数组,定义已经排列过的串为:相邻两项a[i],a[i+1],满足a[i]<=a[i+1].我们每次对当前数组删除非排序过的串,合并剩下的串,继续删,直到排序完成. 解法:双向链表模拟过程,设置一个队列,用于存可能产生非排序过的串的头结点,每次从队列中拿出一个头结点判断后面的情况,若还能继续删除,则将头结点的上一个结点放入队列继续判,知道没有别的结点为止. #include…

背包问题,由于数据大不容易dp,改为剪枝,先按性价比排序,若剩下的背包空间都以最高性价比选时不会比已找到的最优解更好时则剪枝,即 if(val + (LD)pk[d].val / (LD)pk[d].w * (lim - w) + EPS <= ans){ return; } 没想到一发过,0ms #include<cstdio> #include<iostream> #include<cstdlib> #include<cstring> #inclu…

Barricade Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description The empire is under attack again. The general of empire is planning to defend his castle. The land can be seen as N towns and M roads, a…