Sempr == The Best Problem Solver? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 1490    Accepted Submission(s): 970 Problem Description As is known to all, Sempr(Liangjing Wang) had solved mor…

Problem Description As is known to all, Sempr(Liangjing Wang) had solved more than 1400 problems on POJ, but nobody know the days and nights he had spent on solving problems. Xiangsanzi(Chen Zhou) was a perfect problem solver too. Now this is a story…

题目传送门 /* 水题:看见x是十的倍数就简单了 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <string> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; int main(void) //HDOJ 4716…

题目传送门 /* 题意:告诉一个区间[L,R],问根节点的n是多少 DFS+剪枝:父亲节点有四种情况:[l, r + len],[l, r + len - 1],[l - len, r],[l - len -1,r]; */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <queue> using namespace std;…

HDOJ(HDU).1016 Prime Ring Problem (DFS) [从零开始DFS(3)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…

题目传送门 /* 这题可以用stl的mutiset容器方便求解,我对这东西不熟悉,TLE了几次,最后用读入外挂水过. 题解有O(n)的做法,还以为我是侥幸过的,后来才知道iterator it写在循环内才超时了,囧! */ /************************************************ Author :Running_Time Created Time :2015-8-4 12:10:11 File Name :G.cpp ******************…

rt 稳定婚姻匹配问题 The Stable Marriage Problem Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 438    Accepted Submission(s): 222 Problem Description The stable marriage problem consists of matching m…

其实是求树上的路径间的数据第K大的题目.果断主席树 + LCA.初始流量是这条路径上的最小值.若a<=b,显然直接为s->t建立pipe可以使流量最优:否则,对[0, 10**4]二分得到boundry,使得boundry * n_edge - sum_edge <= k/b, 或者建立s->t,然后不断extend s->t. /* 4729 */ #include <iostream> #include <sstream> #include <…

The King’s Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2259    Accepted Submission(s): 795 Problem Description In the Kingdom of Silence, the king has a new problem. There are N citi…

Problem Description We once did a lot of recursional problem . I think some of them is easy for you and some if hard for you. Now there is a very easy problem . I think you can AC it. We can define sum(n) as follow: if i can be divided exactly by 3 s…